Android：在sqlite中搜索三列

Im编写一个应用程序，记录所有连接单元的单元塔ID，并将值写入数据库

ID列\操作\ ID LAC CID

xxxxx xxxxx XXXXXX

我的代码：

  public String findProduct(String lacId) {
        String query = "Select * FROM " + TABLE_TOWERS + " WHERE " + COLUMN_LAC + " =  \"" + lacId + "\"";

        SQLiteDatabase db = this.getWritableDatabase();

        Cursor cursor = db.rawQuery(query, null);

        String lac = null;

        if (cursor.moveToFirst()) {
            cursor.moveToFirst();
            lac =cursor.getString(2);
            cursor.close();
        } else {
            lac = null;
        }
            db.close();
        return lac;
    }    

但是，通过这段代码，我得到了包含这个编号的所有行。我想实现一个函数来搜索Op_Id、lac和cid的所有三列，以缩小搜索范围并进一步缩小搜索范围。但是，我无法搜索所有三列以缩小搜索范围

例如

如何设计这样的函数？ 谢谢，萨希尔解决了

 public String findID(String lacId, String opId, String cid) {
        String query = "Select * FROM " + TABLE_TOWERS + " WHERE " + COLUMN_LAC + " = \"" + lacId + "\" AND " + COLUMN_OPERATOR_ID + " = \"" + opId + "\" AND " + COLUMN_CID + " = \"" + cid + "\"";

        System.out.println(query);
        SQLiteDatabase db = this.getWritableDatabase();

        Cursor cursor = db.rawQuery(query, null);

        String id= null;

        if (cursor.moveToFirst()) {
            cursor.moveToFirst();
            lac =cursor.getString(0);
            cursor.close();
        } else {
            id = null;
        }
            db.close();
        return id;
    }

---

…你的问题是？在where子句中可以有很多条件。CID=CID和LAC=LAC，以此类推。

 public String findID(String lacId, String opId, String cid) {
        String query = "Select * FROM " + TABLE_TOWERS + " WHERE " + COLUMN_LAC + " = \"" + lacId + "\" AND " + COLUMN_OPERATOR_ID + " = \"" + opId + "\" AND " + COLUMN_CID + " = \"" + cid + "\"";

        System.out.println(query);
        SQLiteDatabase db = this.getWritableDatabase();

        Cursor cursor = db.rawQuery(query, null);

        String id= null;

        if (cursor.moveToFirst()) {
            cursor.moveToFirst();
            lac =cursor.getString(0);
            cursor.close();
        } else {
            id = null;
        }
            db.close();
        return id;
    }