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添加&;在Android中以编程方式删除TextView_Android_Textview - Fatal编程技术网

添加&;在Android中以编程方式删除TextView

添加&;在Android中以编程方式删除TextView,android,textview,Android,Textview,我成功地以编程方式添加了TextView。。。但我的问题是,如何通过编程删除TextView。。。这是我的密码 MainActivity.java package com.example.textviewdemo; 导入android.os.Bundle; 导入android.support.v7.app.ActionBarActivity; 导入android.view.view; 导入android.widget.Button; 导入android.widget.EditText; 导入

我成功地以编程方式添加了TextView。。。但我的问题是,如何通过编程删除TextView。。。这是我的密码



MainActivity.java

package com.example.textviewdemo;
导入android.os.Bundle;
导入android.support.v7.app.ActionBarActivity;
导入android.view.view;
导入android.widget.Button;
导入android.widget.EditText;
导入android.widget.LinearLayout;
导入android.widget.TextView;

公共类MainActivity扩展了ActionBarActivity{ 私人文本视图添加电视; 私人编辑文本edt; 专用按钮添加、删除; @凌驾 创建时受保护的void(Bundle savedInstanceState){ super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); edt=(EditText)findViewById(R.id.editText1); add=(按钮)findViewById(R.id.button1); delete=(按钮)findviewbyd(R.id.button2); 最终线性布局ll=(线性布局)findViewById(R.id.LinearLayout); add.setOnClickListener(新视图.OnClickListener(){ @凌驾 公共void onClick(视图v){ int no=Integer.parseInt(edt.getText().toString());
对于(int i=1;i将所有文本视图存储在一个数组中,并执行您想要的操作。现在
addTv
是最后创建的文本视图。此外,如果在添加之前单击“删除”,您将获得NullPointerException

另请参见:和

(int i=0;i
package com.example.textviewdemo;
import android.os.Bundle;
import android.support.v7.app.ActionBarActivity;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.LinearLayout;
import android.widget.TextView;
<br>
public class MainActivity extends ActionBarActivity {

    private TextView addTv;
    private EditText edt;
    private Button add, delete;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        edt = (EditText) findViewById(R.id.editText1);
        add = (Button) findViewById(R.id.button1);
        delete = (Button) findViewById(R.id.button2);
        final LinearLayout ll = (LinearLayout) findViewById(R.id.LinearLayout);

        add.setOnClickListener(new View.OnClickListener() {

            @Override
            public void onClick(View v) {
                int no = Integer.parseInt(edt.getText().toString());
                for (int i = 1; i <= no; i++) {
                    addTv = new TextView(MainActivity.this);
                    addTv.setText("TextView " + i);
                    addTv.setId(i);
                    ll.addView(addTv);
                }
            }
        });
        delete.setOnClickListener(new View.OnClickListener() {

            @Override
            public void onClick(View v) {
                int no1 = Integer.parseInt(edt.getText().toString());
                for (int i = 1; i <= no1; i++) {
                    ll.removeView(addTv);
                }
            }
        });
    }
}
for(int i = 0; i<ll.getChildrenCount(); i++){
    if(ll.getChildAt(i) instanceof TextView){
        ll.removeView(ll.getChildAt(i));
    } 
}