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Android 使用改装2响应车身为空_Android_Api_Retrofit2_Response - Fatal编程技术网

Android 使用改装2响应车身为空

Android 使用改装2响应车身为空,android,api,retrofit2,response,Android,Api,Retrofit2,Response,所以我在《邮递员》中尝试了这个请求,效果很好。但是当我在Android中执行此操作时,response.body()是空的。该请求发送一封电子邮件和登录密码,并应返回用户对象和其他详细信息 loginUser.enqueue(new Callback<User>() { @Override public void onResponse(Call<User> call, Response<User> respons

所以我在《邮递员》中尝试了这个请求,效果很好。但是当我在Android中执行此操作时,response.body()是空的。该请求发送一封电子邮件和登录密码,并应返回用户对象和其他详细信息

loginUser.enqueue(new Callback<User>() {
            @Override
            public void onResponse(Call<User> call, Response<User> response) {
                if (response.isSuccessful()) {
                   loginView.onLoginResult(response.body());
                } else {
                    loginView.showLoginErrorResult();
                }
            }
}

我的用户类:

public class User {

@SerializedName("id")
@Expose
private String id;

@SerializedName("token")
@Expose
private String token;

@SerializedName("email")
@Expose
private String email;

@SerializedName("firstName")
@Expose
private String firstName;

@SerializedName("lastName")
@Expose
private String lastName;

public User(String id, String token, String email, String firstName, String lastName) {
    this.id = id;
    this.token = token;
    this.email = email;
    this.firstName = firstName;
    this.lastName = lastName;
}
   //getters &setters...
}
邮递员要求:

{
    "email":"test@email.com",
    "password":"123456"
}
邮递员回应:

{
    "success": true,
    "payload": {
        "email": "test@email.com",
        "firstName": "test",
        "lastName": "test",
    }
}

我也收到了200条回复,但没有关于身体的数据。创建一个这样的新模型

public class ResponseApi{
        boolean success;
        User payload;

        public boolean isSuccess() {
            return success;
        }

        public void setSuccess(boolean success) {
            this.success = success;
        }

        public User getPayload() {
            return payload;
        }

        public void setPayload(User payload) {
            this.payload = payload;
        }

    }
public interface NetworkAPI {

   @POST("users/login")
   Call< ResponseApi > login(@Body UserLogin userLogin);
}
然后像这样更改代码

public class ResponseApi{
        boolean success;
        User payload;

        public boolean isSuccess() {
            return success;
        }

        public void setSuccess(boolean success) {
            this.success = success;
        }

        public User getPayload() {
            return payload;
        }

        public void setPayload(User payload) {
            this.payload = payload;
        }

    }
public interface NetworkAPI {

   @POST("users/login")
   Call< ResponseApi > login(@Body UserLogin userLogin);
}
公共接口网络API{
@POST(“用户/登录”)
调用login(@Body-UserLogin-UserLogin);
}

希望它能奏效。。实际上,由于结构不同,改型无法解析json对象

请发布改型接口类、示例URL和Postman客户端截图。共享您的用户类和Postman的Json响应。@IntsabHaider我已更新我的postCall登录(@Body UserLogin UserLogin);更改后,您必须从其覆盖或实现的位置更改它。。