SQlite android查询中的LIKE语句错误

我对sqlite android中的LIKE语句有一个问题。我用了一个小时来计算，但我无法得到错误部分。有人知道我的错在哪里吗

    public Cursor getSearch(String id) {

        String[] args = { id };


        return (database.rawQuery("SELECT " + SQLiteHelper.product_id
                + " as _id," 
                + SQLiteHelper.productName + " ," +SQLiteHelper.productDesp
                + "," + SQLiteHelper.productQtty + ","
                +SQLiteHelper.product_CategoryF+" FROM " 
                + SQLiteHelper.productTable+"  WHERE "
                + SQLiteHelper.productName +" LIKE 'id%'",null));
}

错误消息

 bind or column index out of range: handle 0x5e3ec0

有人知道我的错在哪里吗

    public Cursor getSearch(String id) {

        String[] args = { id };


        return (database.rawQuery("SELECT " + SQLiteHelper.product_id
                + " as _id," 
                + SQLiteHelper.productName + " ," +SQLiteHelper.productDesp
                + "," + SQLiteHelper.productQtty + ","
                +SQLiteHelper.product_CategoryF+" FROM " 
                + SQLiteHelper.productTable+"  WHERE "
                + SQLiteHelper.productName +" LIKE 'id%'",null));
}

解决方案

return (database.rawQuery("SELECT " + SQLiteHelper.product_id
                + " as _id," 
                + SQLiteHelper.productName + " ," +SQLiteHelper.productDesp
                + "," + SQLiteHelper.productQtty + ","
                +SQLiteHelper.product_CategoryF+" FROM " 
                + SQLiteHelper.productTable+"  WHERE "
                + SQLiteHelper.productName +" LIKE '"+id+"%'",null));

---

您不需要像这样形成SQL

rawQuery

使绑定参数变得非常容易

rawQuery("SELECT ? as _id, ?, ?, ?, ? FROM ? WHERE ? LIKE 'id%'", new String[] {SQLiteHelper.product_id, SQLiteHelper.productName, SQLiteHelper.productDesp, SQLiteHelper.productQtty, SQLiteHelper.product_CategoryF, SQLiteHelper.productTable, SQLiteHelper.productName});

就您的代码而言，请注意，

，“+

在您的分类行上应该是

+”，

---

检查以下语法：-“+SQLiteHelper.product_CategoryF+”from”。删除此“”。在like中，它应该是这样的“like'”+id+“%”，null。试试这个好的，谢谢你的帮助…我知道我的错误。。