Android,无法使用用户id检索电话号码
我正在尝试在选取活动中选择某个用户后检索该用户的电话号码 以下是启动活动的代码:Android,无法使用用户id检索电话号码,android,android-cursor,phone-number,Android,Android Cursor,Phone Number,我正在尝试在选取活动中选择某个用户后检索该用户的电话号码 以下是启动活动的代码: Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.CommonDataKinds.Phone.CONTENT_URI); startActivityForResult(intent, Constants.COMMUNICATION_CONFIG_RESULT); 这是用于检索用户名、id和电话号码的代码,用于onActivityResu
Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.CommonDataKinds.Phone.CONTENT_URI);
startActivityForResult(intent, Constants.COMMUNICATION_CONFIG_RESULT);
这是用于检索用户名、id和电话号码的代码,用于onActivityResult:
Uri contactData = data.getData();
ContentResolver cr = getContentResolver();
Cursor cursor = cr.query(contactData, null, null, null, null);
if (cursor.moveToFirst()) {
String contactId =
cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone._ID));
String name = cursor.getString(
cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
String hasPhone =
cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));
if (hasPhone.equalsIgnoreCase("1")) {
Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ contactId,null, null);
phones.moveToFirst();
String contactNumber = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
Log.i("phoneNUmber", "The phone number is "+ contactNumber);
}
}
我总是得到用户名和id,用户总是有电话号码,但无论选择了哪个用户,光标电话总是空的
为什么我找不到电话号码?发现了问题。它必须是:
// try this way,hope this will help you...
Intent i = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(i, 1);
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (resultCode == RESULT_OK) {
String phoneNumber = getPhoneNumber(data.getData());
if (phoneNumber.trim().length() > 0) {
// use this phoneNumber
} else {
ting("Phone Number Not Founded ...");
}
}
}
private String getPhoneNumber(Uri contactInfo) {
String phoneNumbers = "";
Cursor cursor = getContentResolver().query(contactInfo, null, null, null, null);
while (cursor.moveToNext()) {
String contactId = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));
String hashPhone = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));
if ("1".equalsIgnoreCase(hashPhone)) {
Cursor contactCursor = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = " + contactId, null, null);
while (contactCursor.moveToNext()) {
int type = contactCursor.getInt(contactCursor.getColumnIndex(Phone.TYPE));
if (type == Phone.TYPE_MOBILE) {
int colIdx = contactCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
phoneNumbers = phoneNumbers.concat(contactCursor.getString(colIdx));
break;
}
}
contactCursor.close();
}
}
cursor.close();
return phoneNumbers;
}
String contactId = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.CONTACT_ID));
如果我通过以下方式查询电话号码:
Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ contactId,null, null);
问题是我为查询选择了不同的字段