如何检测已经与android设备连接的OTG电缆？

我可以检测OTG电缆是否连接或分离。但当应用程序运行时，如何检测OTG电缆是否已经连接。我的应用程序仅检测otg电缆是否连接或断开

  public class BootUpReceiver extends BroadcastReceiver {

    @Override
    public void onReceive(Context context, Intent intent) {
        String action = intent.getAction();
        Log.e("USB", "Decive Connected -> " + action);

        if (action.equalsIgnoreCase(ACTION_USB_ATTACHED)) {

            UsbDevice device = (UsbDevice) intent
                    .getParcelableExtra(UsbManager.EXTRA_DEVICE);
            if (device != null) {
                int vendorID = device.getVendorId();
                int productID = device.getProductId();

                //If Product and Vendor Id match then set boolean "true" in global variable
                tv_otg.setText("External OTG storage device connected !");
                Log.e("true", "true");

            }

        } else if (action.equalsIgnoreCase(ACTION_USB_DETACHED)) {
            //When ever device Detach set your global variable to "false"
            tv_otg.setText("External OTG storage device disconnected !");
            Log.e("ACTION_USB_DETACHED", "ACTION_USB_DETACHED");
        }


    }
}

  bootupreceiver = new BootUpReceiver();
        IntentFilter filter = new IntentFilter();
        filter.addAction(ACTION_USB_ATTACHED);
        filter.addAction(ACTION_USB_DETACHED);

        filter.setPriority(100);

        registerReceiver(bootupreceiver, filter);

UsbManager-manager=（UsbManager）getSystemService（Context.USB_-SERVICE）；
...
HashMap deviceList=manager.getDeviceList（）；
迭代器deviceIterator=deviceList.values（）.Iterator（）；
while（deviceIterator.hasNext（））{
UsbDevice device=deviceIterator.next（）；
//检查设备检查名称逻辑的代码
}

---

当我插入充电电缆时，Check

为我提供空列表

UsbManager manager = (UsbManager) getSystemService(Context.USB_SERVICE);
...
HashMap<String, UsbDevice> deviceList = manager.getDeviceList();
Iterator<UsbDevice> deviceIterator = deviceList.values().iterator();
while(deviceIterator.hasNext()){
    UsbDevice device = deviceIterator.next();
    //your code for check device check name logic
}