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Android PhoneGap ajax(json调用)_Android_Jquery_Ajax_Json_Cordova - Fatal编程技术网

Android PhoneGap ajax(json调用)

Android PhoneGap ajax(json调用),android,jquery,ajax,json,cordova,Android,Jquery,Ajax,Json,Cordova,我有一个Android应用程序,其中包含对我的远程服务器的ajax json调用。我已经用eclipse,一个模拟器(Ripple)测试了这个应用程序,并在本地服务器的浏览器中测试了ajax脚本。所有的测试都能很好地工作,但当我将我的应用程序上传到PhoneGap Build并在手机上测试apk文件时,ajax调用返回状态0。我做错了什么?仿真器和apk之间会有区别吗 Ajax调用: var formData = $("#form-id").serialize(); $.ajax({ url:

我有一个Android应用程序,其中包含对我的远程服务器的ajax json调用。我已经用eclipse,一个模拟器(Ripple)测试了这个应用程序,并在本地服务器的浏览器中测试了ajax脚本。所有的测试都能很好地工作,但当我将我的应用程序上传到PhoneGap Build并在手机上测试apk文件时,ajax调用返回状态0。我做错了什么?仿真器和apk之间会有区别吗

Ajax调用:

var formData = $("#form-id").serialize();

$.ajax({
url: "https://mydomain.com/file.php",
data: formData, 
type: 'POST',
dataType: 'json',
timeout: 5000,
success: function(data){
    if(data['login'] == 'correct' && data['token'] != 'undefined' ){ 

        window.localStorage["token"] = data['tokenMyMen'];      
        notifyAlert('Login correct', 'Login');

    }else{
        notifyAlert('Login incorrect', 'Login');
    }

},          
error: function(x,e){
    if(x.status==0){
        notifyAlert('You are offline!!\n Please Check Your Network.', 'Error');
    }else if(x.status==404){
        notifyAlert('Requested URL not found.', 'Error');
    }else if(x.status==500){
        notifyAlert('Internel Server Error.', 'Error');
    }else if(e=='parsererror'){
        notifyAlert('Error.\nParsing JSON Request failed. '+x.status, 'Error');
    }else if(e=='timeout'){
        notifyAlert('Request Time out.');
    }else {
        notifyAlert('Unknow Error.\n'+x.responseText, 'Error');
    }
}});
config.xml具有

远程服务器具有:

if($this->user->login($username, $password)){   

    $token = $this->user->getProperty('token');
    $createArray = array();             
    $createArray['login'] = 'correct';
    $createArray['token'] = $token;     

    $record = $createArray;
    echo json_encode($record);

}else{
    $record = array('login' => 'incorrect');                
    echo json_encode($record);
}