解压文件夹在android中出现FileNotFound异常

解压文件夹在android中出现FileNotFound异常,android,unzip,Android,Unzip,我正在尝试解压文件夹到文件夹,它的工作,它解压了一些文件夹,但当它采取index.html它给出这样的错误,我想解压文件到文件夹,但我得到了一个错误,我该如何解决这个问题 W/System.err: java.io.FileNotFoundException: /storage/emulated/0/Android/data/com.kocsistem.pixageoneandroid/files/Contents/widgetContent/ab34f7fe018a45f0a43d3139d6

我正在尝试解压文件夹到文件夹,它的工作,它解压了一些文件夹,但当它采取index.html它给出这样的错误,我想解压文件到文件夹,但我得到了一个错误,我该如何解决这个问题

W/System.err: java.io.FileNotFoundException: /storage/emulated/0/Android/data/com.kocsistem.pixageoneandroid/files/Contents/widgetContent/ab34f7fe018a45f0a43d3139d6986b84/index.html (No such file or directory)
        at java.io.FileOutputStream.open0(Native Method)
W/System.err:     at java.io.FileOutputStream.open(FileOutputStream.java:308)
        at java.io.FileOutputStream.<init>(FileOutputStream.java:238)
        at java.io.FileOutputStream.<init>(FileOutputStream.java:180)
        at com.kocsistem.pixageoneandroid.utils.Utils.unpackZip(Utils.java:454)
        at 
请尝试使用以下代码:

1.首先创建zip文件

                File FPath = new File(folder.getAbsolutePath() + File.separator + folderName);
                if (FPath.exists()) FPath.delete();
                String mPath = folder.getAbsolutePath() + File.separator + folderName+ ".zip";



                FileOutputStream fos = new FileOutputStream(mPath);
                InputStream is = cn.getInputStream();
                int bytesRead = 0;
                byte[] buf = new byte[8096];
                long total = 0;
                int progress;
                int count = i;
                while ((bytesRead = is.read(buf)) != -1) {
                    total += bytesRead;
                    fos.write(buf, 0, bytesRead);
                }
                if (is != null) is.close();
                if (fos != null) {
                    fos.flush();
                    fos.close();
                }
2.创建文件时

 unpackZip(folder.getAbsolutePath() + File.separator, folderName);
3.你的职能

 private boolean unpackZip(String path, String folderName) {

    InputStream is;
    ZipInputStream zis;
    try {
        String filename;
        is = new FileInputStream(path + folderName+ ".zip");
        zis = new ZipInputStream(new BufferedInputStream(is));
        ZipEntry ze;
        byte[] buffer = new byte[1024];
        int count;

        File refolder = new File(path + folderName);
        if (!refolder.exists())
            refolder.mkdirs();


        while ((ze = zis.getNextEntry()) != null) {
            filename = ze.getName();
            if (ze.isDirectory()) {
                File fmd = new File(refolder.getAbsolutePath() + "/" + filename);
                fmd.mkdirs();
                continue;
            }

            FileOutputStream fout = new FileOutputStream(refolder.getAbsolutePath() + "/" + filename);
            while ((count = zis.read(buffer)) != -1) {
                fout.write(buffer, 0, count);
            }

            fout.close();
            zis.closeEntry();
        }

        zis.close();
    } catch (IOException e) {
        e.printStackTrace();
        return false;
    } finally {
        File mFF = new File(path + folderName+ ".zip");
        mFF.delete();
    }

    return true;
}
格雷德尔先生

zip4j
实现'com.github.joielechong:zip4jandroid:1.0.1'

allprojects {
    repositories {
        maven { url "https://jitpack.io" }

    }
}
代码


if(!refolder.exists())if(!refolder.mkdirs()){Toast(…抱歉无法创建目录…);return;}
File fmd=new File(refolder.getAbsolutePath()+“/”+filename)更好:
文件fmd=新文件(重新文件夹,文件名)
is=newfileinputstream(path+folderName+“.zip”)错误。应该是
is=newfileinputstream(路径)如您在原始post.ContextWrapper cw=newcontextwrapper(context)中所见;folder=cw.getDir(“Name”,Context.MODE\u PRIVATE)@blackapps抱歉,请立即检查谢谢,它可以正常工作,不会出现FileNotFound异常
allprojects {
    repositories {
        maven { url "https://jitpack.io" }

    }
}
String source = destFilePath + "/" + fileNameList.get(i);
String target = destFilePath.getAbsolutePath();

    try {
           ZipFile zipFile = new ZipFile(source);
           zipFile.extractAll(target);
         } catch (ZipException e) {
           e.printStackTrace();
           }