Android 如何获取变量的JSON值？

这是我的json值

{"test":"ruslan","status":"OK"}

如何获得测试值

这是我访问api的httpclient代码

AsyncHttpClient client = new AsyncHttpClient();
client.setBasicAuth("user01", "pwd01");
client.get("http://localhost/web/api/getsession", new AsyncHttpResponseHandler() {
      @Override
      public void onSuccess(int statusCode, Header[] headers, byte[] responseBody) {

        // in this section, I want to store test value from json to a variable

      @Override
      public void onFailure(int statusCode, Header[] headers, byte[] responseBody, Throwable error) {
              Log.d("Status", "failure");
          }
      });

---

你可以这样做

    String json = "{\"test\":\"ruslan\",\"status\":\"OK\"}";
    String test = "";
    try {
        JSONObject jsonObject = new JSONObject(json);
        test = jsonObject.getString("test");
    }catch (JSONException je){
        je.printStackTrace();
    }
    System.out.println("test : " + test);

---

首先通过连接服务器从服务器获取ur json

DefaultHttpClient   httpclient = new DefaultHttpClient(new BasicHttpParams());
HttpPost httppost = new HttpPost(http://someJSONUrl/jsonWebService);
// Depends on your web service
httppost.setHeader("Content-type", "application/json");

InputStream inputStream = null;
String result = null;
try {
    HttpResponse response = httpclient.execute(httppost);           
    HttpEntity entity = response.getEntity();

    inputStream = entity.getContent();
    // json is UTF-8 by default
    BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream, "UTF-8"), 8);
    StringBuilder sb = new StringBuilder();

    String line = null;
    while ((line = reader.readLine()) != null)
    {
        sb.append(line + "\n");
    }
    result = sb.toString();
} catch (Exception e) { 
    // Oops
}
finally {
    try{if(inputStream != null)inputStream.close();}catch(Exception squish){}
}

现在你有了JSON，那又怎样

创建JSONObject：

JSONObject jObject = new JSONObject(result);

获取特定字符串的步骤

String aJsonString = jObject.getString("test");

---

下面是如何解析json的示例

    {
   "sys":
   {
      "country":"GB",
      "sunrise":1381107633,
      "sunset":1381149604
   },
   "weather":[
      {
         "id":711,
         "main":"Smoke",
         "description":"smoke",
         "icon":"50n"
      }
   ],

  "main":
   {
      "temp":304.15,
      "pressure":1009,
   }
}

Java代码

 JSONObject sys  = reader.getJSONObject("sys");
country = sys.getString("country");

JSONObject main  = reader.getJSONObject("main");
temperature = main.getString("temp");

---

有关更多详细信息，请参见

为什么不回答这个问题？@cricket_007你说什么不明白？该问题显示了JSON示例，询问如何获得一个值。这可能回答了如何解析JSON的问题，但并没有回答真正的问题，因为这家伙没有告诉JSON的来源，我假设它来自web服务@cricket当然，但额外的细节其实并不重要，对吧？问题是如何解析JSON，而不是从URL1获取数据http://localhost/web/ 不起作用2你的应用程序中的JSON字符串在哪里？您似乎需要首先将字节[]转换为字符串。