Android 合同与履行

我想把所有的联系电话都放到列表视图中。某些联系人有多个电话号码，我想显示以下列表：

Pippo
Number : +393934578987
Pippo
Number : +394578952364
Topolino
Number : +45124578972
Minnie
Number : +39454545445b
Minnie
Number : +39457879758
etc

我使用了一个带有列表和映射的SimpleAdapter，但性能很差…于是我决定使用SimpleCorsorAdapter和for来访问表contacts contract和contacts contract.commonDataTypes.Phone一个游标连接程序，并使用此代码

Cursor cursor = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI, null, ContactsContract.Contacts.HAS_PHONE_NUMBER + "=1", null, null);
Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = " + Contacts._ID, null, null);
        String[] cursor_join = new String[]{
                Contacts._ID,
                ContactsContract.Contacts.DISPLAY_NAME,
                ContactsContract.CommonDataKinds.Phone.NUMBER
        };
        MatrixCursor matrix_cursor = new MatrixCursor(cursor_join);
        CursorJoiner cursor_j = new CursorJoiner(cursor, new String[]{Contacts._ID}, phones, new String[]{ContactsContract.CommonDataKinds.Phone.CONTACT_ID});
        for (CursorJoiner.Result joinerResult : cursor_j) {
            String[] values;
            switch (joinerResult) {         
                case LEFT:             // handle case where a row in cursorA is unique             
                    values = new String[]{
                            cursor.getString(cursor.getColumnIndex(Contacts._ID)),
                            cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME)),
                            phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER))
                        };
                        matrix_cursor.addRow(values);
                    break;         
                case RIGHT:             // handle case where a row in cursorB is unique             
                    break;         
                case BOTH:             // handle case where a row with the same key is in both cursors             
                    values = new String[]{
                            cursor.getString(cursor.getColumnIndex(Contacts._ID)),
                            cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME)),
                            phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER))
                        };
                        matrix_cursor.addRow(values);
                    break;     
            }
        }
        while(matrix_cursor.moveToNext()){
            contactId = matrix_cursor.getInt(matrix_cursor.getColumnIndex(Contacts._ID));
            String name = matrix_cursor.getString(matrix_cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
            String num = matrix_cursor.getString(matrix_cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
        }

但它不起作用

有人告诉我为什么吗

---

谢谢

也许你错过了对

matrix\u cursor.moveToFirst（）的调用

这些天我终于解决了这个问题。我在case LEFT中放置了一些东西，以便在左光标超出范围时移动光标并在case RIGHT中打断（

isAfterLast（）

实际上）

不确定这是否有帮助以及您遇到了什么问题

case LEFT:
rightcursor.moveToPrevious();
......
rightcursor.moveToNext();
break;

case RIGHT:
if(leftcursor.isAfterLast()){break;}
....