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Android 与索尼xperia在onActivityResult中发布_Android_Onactivityresult - Fatal编程技术网

Android 与索尼xperia在onActivityResult中发布

Android 与索尼xperia在onActivityResult中发布,android,onactivityresult,Android,Onactivityresult,我开始活动以获得打开GPS的结果 然后在活动结果中接收。。它在一些手机上工作正常,但索尼却不工作,我不知道为什么 我使用嵌套片段 开始活动 Intent callGPSSettingIntent = new Intent( android.provider.Settings.ACTION_LOCATION_SOURCE_SETTINGS); startA

我开始活动以获得打开GPS的结果 然后在活动结果中接收。。它在一些手机上工作正常,但索尼却不工作,我不知道为什么 我使用嵌套片段 开始活动

Intent callGPSSettingIntent = new Intent(
                                        android.provider.Settings.ACTION_LOCATION_SOURCE_SETTINGS);
                                startActivityForResult(
                                        callGPSSettingIntent, openGPSRequest);
然后在片段中接收

@Override
    public void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);
        if (requestCode == openGPSRequest) {
            try {
                activity.hideProgress();
            } catch (Exception e) {

            }
            activity.replaceCurrentFragment(
                    FramentNavigationMapInside.getInstance(branche), true, true);
        }
    }
主要活动

@Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {

super.onActivityResult(requestCode, resultCode, data);



    }
在每个片段中覆盖ActivityResult

我在lenove和三星进行了测试,效果很好,但索尼xperia不起作用,只在ActivityResult上运行,在主要活动中调用

解决我的问题

在片段世界中我们经常遇到的一个常见问题是:虽然我们可以直接从嵌套片段调用startActivityForResult,但似乎永远不会调用onActivityResult,这给处理嵌套片段的活动结果带来了很多麻烦

解决方案

因此,从现在起,我们将从片段中调用getActivity().startActivityForResult(…),而不仅仅是startActivityResult(…)。像这样:

// In Fragment
Intent intent = new Intent(getActivity(), SecondActivity.class);
getActivity().startActivityForResult(intent, 12345);
因此,所有接收到的结果都将在单个位置处理:片段所在活动的onActivityResult

问题是如何将活动结果发送到Fragment? 因为我们不能以正常的方式,或者至少以简单的方式,直接与所有嵌套片段通信。另一个事实是,每个片段都知道它必须处理哪个请求代码,因为它也是调用startActivityForResult的片段。因此,我们选择了“向当时处于活动状态的每个片段广播,让这些片段检查请求代码并执行它们想要的操作”的方式

说到广播,LocalBroadcastManager可以做这项工作,但机修工太老了。我选择了另一种选择,EventBus,它有很多选择。我选择的是来自广场的奥托。它在性能和健壮性方面非常出色

dependencies {
  compile 'com.squareup:otto:1.3.6'
}
以Otto的方式,让我们创建一个总线事件,作为一个包含这些活动结果值的包

import android.content.Intent;

/**
 * Created by nuuneoi on 3/12/2015.
 */
public class ActivityResultEvent {

    private int requestCode;
    private int resultCode;
    private Intent data;

    public ActivityResultEvent(int requestCode, int resultCode, Intent data) {
        this.requestCode = requestCode;
        this.resultCode = resultCode;
        this.data = data;
    }

    public int getRequestCode() {
        return requestCode;
    }

    public void setRequestCode(int requestCode) {
        this.requestCode = requestCode;
    }

    public int getResultCode() {
        return resultCode;
    }

    public void setResultCode(int resultCode) {
        this.resultCode = resultCode;
    }

    public Intent getData() {
        return data;
    }

    public void setData(Intent data) {
        this.data = data;
    }
}

import android.os.Handler;
import android.os.Looper;

import com.squareup.otto.Bus;

/**
 * Created by nuuneoi on 3/12/2015.
 */
public class ActivityResultBus extends Bus {

    private static ActivityResultBus instance;

    public static ActivityResultBus getInstance() {
        if (instance == null)
            instance = new ActivityResultBus();
        return instance;
    }

    private Handler mHandler = new Handler(Looper.getMainLooper());

    public void postQueue(final Object obj) {
        mHandler.post(new Runnable() {
            @Override
            public void run() {
                ActivityResultBus.getInstance().post(obj);
            }
        });
    }

}
在活动中

public class MainActivity extends ActionBarActivity {

    ...

    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);
        ActivityResultBus.getInstance().postQueue(
                    new ActivityResultEvent(requestCode, resultCode, data));
    }

    ...

}
最后,在片段中处理activityresult上的数据

public class BodyFragment extends Fragment {

    ...

    @Override
    public void onStart() {
        super.onStart();
        ActivityResultBus.getInstance().register(mActivityResultSubscriber);
    }

    @Override
    public void onStop() {
        super.onStop();
        ActivityResultBus.getInstance().unregister(mActivityResultSubscriber);
    }

    private Object mActivityResultSubscriber = new Object() {
        @Subscribe
        public void onActivityResultReceived(ActivityResultEvent event) {
            int requestCode = event.getRequestCode();
            int resultCode = event.getResultCode();
            Intent data = event.getData();
            onActivityResult(requestCode, resultCode, data);
        }
    };
 @Override
    public void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);
        // Don't forget to check requestCode before continuing your job
        if (requestCode == 12345) {
            // Do your job
            tvResult.setText("Result Code = " + resultCode);
        }
    }
    ...

}

希望这段代码能帮助任何人面对这个问题

我想这将是索尼支持的问题。。。