Ansible使用通配符/regex/glob删除文件,但有例外

Ansible使用通配符/regex/glob删除文件,但有例外,ansible,Ansible,我想删除基于通配符的文件,但也要向规则中添加例外 - hosts: all tasks: - name: Ansible delete file wildcard find: paths: /etc/wild_card/example patterns: "*.txt" use_regex: true register: wildcard_files_to_delete - name: Ansible remo

我想删除基于通配符的文件,但也要向规则中添加例外

- hosts: all
  tasks:
  - name: Ansible delete file wildcard
    find:
      paths: /etc/wild_card/example
      patterns: "*.txt"
      use_regex: true
    register: wildcard_files_to_delete

  - name: Ansible remove file wildcard
    file:
      path: "{{ item.path }}"
      state: absent
    with_items: "{{ wildcard_files_to_delete.files }}"

例如,我想删除一个名为“important.txt”的文件。我该怎么做呢?

只要在删除文件的任务中添加一个
条件即可。例如,类似于:

  - name: Ansible remove file wildcard
    file:
      path: "{{ item.path }}"
      state: absent
    when: item.path != '/etc/wild_card/example/important.txt'
    with_items: "{{ wildcard_files_to_delete.files }}"
这将跳过特定文件。如果您有要跳过的文件列表,您可以改为:

  - name: Ansible remove file wildcard
    file:
      path: "{{ item.path }}"
      state: absent
    when: item.path not in files_to_skip
    with_items: "{{ wildcard_files_to_delete.files }}"
    vars:
      files_to_skip:
        - /etc/wild_card/example/important.txt
        - /etc/wild_card/example/saveme.txt
如果您想基于某种模式保留文件,可以使用ansible的
匹配
搜索
测试:

  - name: Ansible remove file wildcard
    file:
      path: "{{ item.path }}"
      state: absent
    when: item.path is not search('important.txt')
    with_items: "{{ wildcard_files_to_delete.files }}"