Apache spark 无法在SPARK数据帧上创建临时视图
下面是示例代码Apache spark 无法在SPARK数据帧上创建临时视图,apache-spark,Apache Spark,下面是示例代码 spark-shell --master yarn val hive_location = "hive_meta_loc" val spark =org.apache.spark.sql.SparkSession.builder().appName("WNGDEVICES").config("spark.sql.warehouse.dir", "hive_location").enableHiveSupport().getOrCreate() val rawdata = s
spark-shell --master yarn
val hive_location = "hive_meta_loc"
val spark =org.apache.spark.sql.SparkSession.builder().appName("WNGDEVICES").config("spark.sql.warehouse.dir", "hive_location").enableHiveSupport().getOrCreate()
val rawdata = spark.sql("SELECT * from <table name>")
rawdata.createOrReplaceTempView("Rawdata")
spark-shell——母纱
val hive\u location=“hive\u meta\u loc”
val spark=org.apache.spark.sql.SparkSession.builder().appName(“WNGDEVICES”).config(“spark.sql.warehouse.dir”,“配置单元位置”).enableHiveSupport().getOrCreate()
val rawdata=spark.sql(“选择*from”)
createOrReplaceTempView(“rawdata”)
当我执行此操作时,出现以下错误
请将屏幕截图替换为文本。图像对有视觉障碍的用户(通常依赖于)没有好处,在移动设备上提供的体验很差,搜索引擎无法访问。这看起来像是权限问题。您能对该表进行计数或获取该表的第一条记录吗?我可以使用数据框查看数据,方法是说rawdata.show这是永久性问题,谢谢@morfious902002