Apache spark 使用聚合函数对列中的数组求和
我试图对包含数组的字段求和Apache spark 使用聚合函数对列中的数组求和,apache-spark,apache-spark-sql,Apache Spark,Apache Spark Sql,我试图对包含数组的字段求和 a = sc.parallelize([("a", [1,1,1]), ("a", [2,2])]) a = a.toDF(["g", "arr_val"]) a.registerTempTable('a') sql = """ select aggregate(arr_val, 0, (acc, x) -> acc + x) as sum from a """ spark.sql(sql).show() 但我
a = sc.parallelize([("a", [1,1,1]),
("a", [2,2])])
a = a.toDF(["g", "arr_val"])
a.registerTempTable('a')
sql = """
select
aggregate(arr_val, 0, (acc, x) -> acc + x) as sum
from a
"""
spark.sql(sql).show()
但我遇到了以下错误:
An error occurred while calling o24.sql.
: org.apache.spark.sql.AnalysisException: cannot resolve 'aggregate(a.`arr_val`, 0, lambdafunction((CAST(namedlambdavariable() AS BIGINT) + namedlambdavariable()), namedlambdavariable(), namedlambdavariable()), lambdafunction(namedlambdavariable(), namedlambdavariable()))' due to data type mismatch: argument 3 requires int type, however, 'lambdafunction((CAST(namedlambdavariable() AS BIGINT) + namedlambdavariable()), namedlambdavariable(), namedlambdavariable())' is of bigint type.; line 3 pos 0;
如何使其工作?您需要将累加器中的值转换为浮点数:
a = sc.parallelize([("a", [1,1,1]),
("a", [2,2])])
a = a.toDF(["g", "arr_val"])
a.registerTempTable('a')
sql = """
select
aggregate(arr_val, cast(0 as float), (acc, x) -> acc + cast(x as float)) as sum
from a
"""
spark.sql(sql).show()