Apache spark 值序列不是对象贝叶斯的成员

我是spark的新手，尝试使用文档示例中的MLlib-NaiveBayes。我试图导入NaiveBayes，但我得到以下错误，其中提到它没有train方法。我不知道该怎么做？如果您有任何意见，这将是有益的

import org.apache.spark.{SparkConf, SparkContext}
import org.apache.spark.mllib.linalg.Vectors
import org.apache.spark.mllib.regression.LabeledPoint
import org.apache.spark.mllib.classification.NaiveBayes


object NaiveBayes {

def main(args: Array[String]){

val conf = new SparkConf().setMaster("local[1]").setAppName("NaiveBayesExample")
val sc = new SparkContext(conf)

val data = sc.textFile("/Users/Desktop/Studies/sample_naive_bayes_data.txt")
val parsedData = data.map { line =>
  val parts = line.split(',')
  LabeledPoint(parts(0).toDouble, Vectors.dense(parts(1).split(' ').map(_.toDouble)))
}

// Split data into training (60%) and test (40%).
val splits = parsedData.randomSplit(Array(0.6, 0.4), seed = 11L)
val training = splits(0)
val test = splits(1)

val model = NaiveBayes.train(training, lambda = 1.0)

val predictionAndLabel = test.map(p => (model.predict(p.features), p.label))
val accuracy = 1.0 * predictionAndLabel.filter(x => x._1 == x._2).count() / test.count()

println("Accuracy = " + accuracy * 100 + "%")

}
 }

错误：

 Error:(26, 28) value train is not a member of object NaiveBayes
    val model = NaiveBayes.train(training, lambda = 1.0)
                       ^
 Error:(29, 59) value _1 is not a member of Nothing
   val accuracy = 1.0 * predictionAndLabel.filter(x => x._1 == x._2).count() / test.count()
                                                      ^

---

在您的程序中，您正在重新定义对象

NaiveBayes

，以便spark无法访问mllib对象。

---

将

object NaiveBayes

重命名为

object MyNaiveBayes

，以防止出现这种情况。

在您的程序中，您正在重新定义对象

NaiveBayes

，以便spark无法访问mllib对象。 将

object NaiveBayes

重命名为

object MyNaiveBayes

，以防止出现这种情况