使用applescript获取字符串的前几个字符

我希望在applescript中只保留字符串的前13个字符。我想我不明白如何使用“characters”功能。 有人能帮我吗

choose from list {"0041325677667-pharmacie 1", "0041325677557-pharmacie 2",
"0041325677447-pharmacie 3", "0041325677337-pharmacie 4"} with prompt 
"Thanks to select" without multiple selections allowed and empty selection allowed 
return the result as string 
return characters 1 thru 13 of result

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提前感谢您的帮助

字符x到y

返回字符列表，在您的示例中，项目1返回

{"0", "0", "4" ,"1" ,"3" ,"2" ,"5" ,"6" ,"7" ,"7" ,"6" ,"6", "7"}

文本x到y

根据请求返回字符串

默认情况下，

不允许多个选择，允许空选择

，因此可以省略。但是，当用户按下“取消”时，应该考虑该情况，然后表达式返回布尔<代码> false <代码> > < /p>

set chosen to choose from list {"0041325677667-pharmacie 1", "0041325677557-pharmacie 2", "0041325677447-pharmacie 3", "0041325677337-pharmacie 4"} with prompt "Thanks to select"
if chosen is false then return "" -- in case of 'Cancel' return empty string
return text 1 thru 13 of (item 1 of chosen) -- as chosen returns a list by default it must be flattened