Arrays 使用ruby中不同哈希数组中的元素创建哈希
在一次训练营练习中,我们获得了以下阵列:Arrays 使用ruby中不同哈希数组中的元素创建哈希,arrays,ruby,hash,Arrays,Ruby,Hash,在一次训练营练习中,我们获得了以下阵列: library = [ { "title" => "Hitchhiker's Guide", "Author" => "Douglas Adams", "categories" => [ "comedy", "fiction", "british"] }, { "title" => "Pride and Prejudice", "Author" => "Jane Au
library = [
{
"title" => "Hitchhiker's Guide",
"Author" => "Douglas Adams",
"categories" => [ "comedy", "fiction", "british"]
},
{
"title" => "Pride and Prejudice",
"Author" => "Jane Austen",
"categories" => [ "morality", "fiction", "society", "british"]
},
{
"title" => "Search Inside Yourself",
"Author" => "Chade-Meng Tan",
"categories" => [ "self improvement", "non-fiction", "mindfulness", "business"]
},
{
"title" => "Benjamin Franklin: An American Life",
"Author" => "Walter Isaacson",
"categories" => [ "non-fiction", "history", "founding fathers"]
},
{
"title" => "Glengarry Glen Ross",
"Author" => "David Mamet",
"categories" => [ "play", "fiction", "drama"]
}
]
我们需要创建一个新的散列,其中类别作为元素,标题作为值
我知道如何创建一个类别\u散列
,但我不知道如何将标题附加到每个类别。这是我的密码:
category_hash = {}
sub_category = []
library.each do |book|
book["categories"].each do |category|
sub_category << category
end
sub_category.each do |index|
category_hash[index] = "I'm not sure how to append the titles here"
end
end
p category_hash
category_hash={}
子类别=[]
图书馆。每本书|
书籍[“类别”]。每一本书都有一个类别|
子类别您可以使用:
您可以使用:
这里有另一种方法,比@AndreyDeineko的答案效率低
library.map{|h| h.values_at("categories", "title")}.to_h
结果:
{
["comedy", "fiction", "british"]=>"Hitchhiker's Guide",
["morality", "fiction", "society", "british"]=>"Pride and Prejudice",
["self improvement", "non-fiction", "mindfulness", "business"]=>"Search Inside Yourself",
["non-fiction", "history", "founding fathers"]=>"Benjamin Franklin: An American Life",
["play", "fiction", "drama"]=>"Glengarry Glen Ross"
}
{
"comedy"=>"Hitchhiker's Guide",
"fiction"=>"Glengarry Glen Ross",
"british"=>"Pride and Prejudice",
"morality"=>"Pride and Prejudice",
"society"=>"Pride and Prejudice",
"self improvement"=>"Search Inside Yourself",
"non-fiction"=>"Benjamin Franklin: An American Life",
"mindfulness"=>"Search Inside Yourself",
"business"=>"Search Inside Yourself",
"history"=>"Benjamin Franklin: An American Life",
"founding fathers"=>"Benjamin Franklin: An American Life",
"play"=>"Glengarry Glen Ross",
"drama"=>"Glengarry Glen Ross"
}
{
"comedy"=>["Hitchhiker's Guide"],
"fiction"=>["Hitchhiker's Guide", "Pride and Prejudice", "Glengarry Glen Ross"],
"british"=>["Hitchhiker's Guide", "Pride and Prejudice"],
"morality"=>["Pride and Prejudice"],
"society"=>["Pride and Prejudice"],
"self improvement"=>["Search Inside Yourself"],
"non-fiction"=>["Search Inside Yourself", "Benjamin Franklin: An American Life"],
"mindfulness"=>["Search Inside Yourself"],
"business"=>["Search Inside Yourself"],
"history"=>["Benjamin Franklin: An American Life"],
"founding fathers"=>["Benjamin Franklin: An American Life"],
"play"=>["Glengarry Glen Ross"],
"drama"=>["Glengarry Glen Ross"]
}
如果您希望通过“category”
属性分发它(当然,这取决于数组中散列项的顺序;我假设您的意思是后面一个比前面一个优先):
结果:
{
["comedy", "fiction", "british"]=>"Hitchhiker's Guide",
["morality", "fiction", "society", "british"]=>"Pride and Prejudice",
["self improvement", "non-fiction", "mindfulness", "business"]=>"Search Inside Yourself",
["non-fiction", "history", "founding fathers"]=>"Benjamin Franklin: An American Life",
["play", "fiction", "drama"]=>"Glengarry Glen Ross"
}
{
"comedy"=>"Hitchhiker's Guide",
"fiction"=>"Glengarry Glen Ross",
"british"=>"Pride and Prejudice",
"morality"=>"Pride and Prejudice",
"society"=>"Pride and Prejudice",
"self improvement"=>"Search Inside Yourself",
"non-fiction"=>"Benjamin Franklin: An American Life",
"mindfulness"=>"Search Inside Yourself",
"business"=>"Search Inside Yourself",
"history"=>"Benjamin Franklin: An American Life",
"founding fathers"=>"Benjamin Franklin: An American Life",
"play"=>"Glengarry Glen Ross",
"drama"=>"Glengarry Glen Ross"
}
{
"comedy"=>["Hitchhiker's Guide"],
"fiction"=>["Hitchhiker's Guide", "Pride and Prejudice", "Glengarry Glen Ross"],
"british"=>["Hitchhiker's Guide", "Pride and Prejudice"],
"morality"=>["Pride and Prejudice"],
"society"=>["Pride and Prejudice"],
"self improvement"=>["Search Inside Yourself"],
"non-fiction"=>["Search Inside Yourself", "Benjamin Franklin: An American Life"],
"mindfulness"=>["Search Inside Yourself"],
"business"=>["Search Inside Yourself"],
"history"=>["Benjamin Franklin: An American Life"],
"founding fathers"=>["Benjamin Franklin: An American Life"],
"play"=>["Glengarry Glen Ross"],
"drama"=>["Glengarry Glen Ross"]
}
这里有另一种方法,比@AndreyDeineko的答案效率低
library.map{|h| h.values_at("categories", "title")}.to_h
结果:
{
["comedy", "fiction", "british"]=>"Hitchhiker's Guide",
["morality", "fiction", "society", "british"]=>"Pride and Prejudice",
["self improvement", "non-fiction", "mindfulness", "business"]=>"Search Inside Yourself",
["non-fiction", "history", "founding fathers"]=>"Benjamin Franklin: An American Life",
["play", "fiction", "drama"]=>"Glengarry Glen Ross"
}
{
"comedy"=>"Hitchhiker's Guide",
"fiction"=>"Glengarry Glen Ross",
"british"=>"Pride and Prejudice",
"morality"=>"Pride and Prejudice",
"society"=>"Pride and Prejudice",
"self improvement"=>"Search Inside Yourself",
"non-fiction"=>"Benjamin Franklin: An American Life",
"mindfulness"=>"Search Inside Yourself",
"business"=>"Search Inside Yourself",
"history"=>"Benjamin Franklin: An American Life",
"founding fathers"=>"Benjamin Franklin: An American Life",
"play"=>"Glengarry Glen Ross",
"drama"=>"Glengarry Glen Ross"
}
{
"comedy"=>["Hitchhiker's Guide"],
"fiction"=>["Hitchhiker's Guide", "Pride and Prejudice", "Glengarry Glen Ross"],
"british"=>["Hitchhiker's Guide", "Pride and Prejudice"],
"morality"=>["Pride and Prejudice"],
"society"=>["Pride and Prejudice"],
"self improvement"=>["Search Inside Yourself"],
"non-fiction"=>["Search Inside Yourself", "Benjamin Franklin: An American Life"],
"mindfulness"=>["Search Inside Yourself"],
"business"=>["Search Inside Yourself"],
"history"=>["Benjamin Franklin: An American Life"],
"founding fathers"=>["Benjamin Franklin: An American Life"],
"play"=>["Glengarry Glen Ross"],
"drama"=>["Glengarry Glen Ross"]
}
如果您希望通过“category”
属性分发它(当然,这取决于数组中散列项的顺序;我假设您的意思是后面一个比前面一个优先):
结果:
{
["comedy", "fiction", "british"]=>"Hitchhiker's Guide",
["morality", "fiction", "society", "british"]=>"Pride and Prejudice",
["self improvement", "non-fiction", "mindfulness", "business"]=>"Search Inside Yourself",
["non-fiction", "history", "founding fathers"]=>"Benjamin Franklin: An American Life",
["play", "fiction", "drama"]=>"Glengarry Glen Ross"
}
{
"comedy"=>"Hitchhiker's Guide",
"fiction"=>"Glengarry Glen Ross",
"british"=>"Pride and Prejudice",
"morality"=>"Pride and Prejudice",
"society"=>"Pride and Prejudice",
"self improvement"=>"Search Inside Yourself",
"non-fiction"=>"Benjamin Franklin: An American Life",
"mindfulness"=>"Search Inside Yourself",
"business"=>"Search Inside Yourself",
"history"=>"Benjamin Franklin: An American Life",
"founding fathers"=>"Benjamin Franklin: An American Life",
"play"=>"Glengarry Glen Ross",
"drama"=>"Glengarry Glen Ross"
}
{
"comedy"=>["Hitchhiker's Guide"],
"fiction"=>["Hitchhiker's Guide", "Pride and Prejudice", "Glengarry Glen Ross"],
"british"=>["Hitchhiker's Guide", "Pride and Prejudice"],
"morality"=>["Pride and Prejudice"],
"society"=>["Pride and Prejudice"],
"self improvement"=>["Search Inside Yourself"],
"non-fiction"=>["Search Inside Yourself", "Benjamin Franklin: An American Life"],
"mindfulness"=>["Search Inside Yourself"],
"business"=>["Search Inside Yourself"],
"history"=>["Benjamin Franklin: An American Life"],
"founding fathers"=>["Benjamin Franklin: An American Life"],
"play"=>["Glengarry Glen Ross"],
"drama"=>["Glengarry Glen Ross"]
}
如果希望一个类别中每本书的列表,并且一本书显示在多个类别中,则可以在将所有未知键设置为包含数组作为值时附加。然后,您只需迭代库中的每本书,并将其标题添加到它所属的每个类别的列表中:
# Pass the category hash a default proc, which will be called
# whenever a key it doesn't have is accessed. So, when you
# encounter a brand new category, it'll already be set up with
# an array
category_hash = Hash.new { |hash, key| hash[key] = [] }
library.each do |book|
book['categories'].each do |category|
# since we passed the default, no worrying, an array will be
# there and we can just add our value into it
category_hash[category] << book['title']
end
end
puts category_hash
还有每个带有\u对象的\u
,因此您可以将其修改为
result = library.each.with_object(Hash.new { |hash, key| hash[key] = [] }) do |book, category_hash|
book['categories'].each do |category|
# since we passed the default, no worrying, an array will be
# there and we can just add our value into it
category_hash[category] << book['title']
end
end
puts result
如果希望一个类别中每本书的列表,并且一本书显示在多个类别中,则可以在将所有未知键设置为包含数组作为值时附加。然后,您只需迭代库中的每本书,并将其标题添加到它所属的每个类别的列表中:
# Pass the category hash a default proc, which will be called
# whenever a key it doesn't have is accessed. So, when you
# encounter a brand new category, it'll already be set up with
# an array
category_hash = Hash.new { |hash, key| hash[key] = [] }
library.each do |book|
book['categories'].each do |category|
# since we passed the default, no worrying, an array will be
# there and we can just add our value into it
category_hash[category] << book['title']
end
end
puts category_hash
还有每个带有\u对象的\u
,因此您可以将其修改为
result = library.each.with_object(Hash.new { |hash, key| hash[key] = [] }) do |book, category_hash|
book['categories'].each do |category|
# since we passed the default, no worrying, an array will be
# there and we can just add our value into it
category_hash[category] << book['title']
end
end
puts result
这与其他答案略有不同
library = [
{title: "Hitch Guide", by: "Doug", cats: ["comedy", "fiction", "british"]},
{title: "P and P", by: "Jane", cats: ["morality", "fiction", "british"]},
{title: "Searchin'", by: "Chad", cats: ["non-fiction", "morality", "gps"]},
{title: "Crazy Ben", by: "Walt", cats: ["non-fiction", "comedy", "dads"]}
]
# => [{:title=>"Hitch Guide", :by=>"Doug", :cats=>["comedy", "fiction", "british"]},
# {:title=>"P and P", :by=>"Jane", :cats=>["morality", "fiction", "british"]},
# {:title=>"Searchin'", :by=>"Chad", :cats=>["non-fiction", "morality", "gps"]},
# {:title=>"Crazy Ben", :by=>"Walt", :cats=>["non-fiction", "comedy", "dads"]}]
library.each_with_object({}) do |g,h|
title = g[:title]
g[:cats].each { |c| (h[c] ||= []) << title }
end
#=> {"comedy"=>["Hitch Guide", "Crazy Ben"],
# "fiction"=>["Hitch Guide", "P and P"],
# "british"=>["Hitch Guide", "P and P"],
# "morality"=>["P and P", "Searchin'"],
# "non-fiction"=>["Searchin'", "Crazy Ben"],
# "gps"=>["Searchin'"],
# "dads"=>["Crazy Ben"]}
库=[
{标题:“搭便车指南”,作者:“道格”,猫:[“喜剧”、“小说”、“英国”]},
{标题:“P和P”,作者:“简”,猫:[“道德”、“小说”、“英国”]},
{标题:“搜索”,作者:“乍得”,猫:[“非小说”、“道德”、“全球定位系统”]},
{标题:“疯狂的本”,作者:“沃尔特”,猫:[“非小说”、“喜剧”、“爸爸”]}
]
#=>[{:title=>“搭便车指南”、:by=>“道格”、:cats=>[“喜剧”、“小说”、“英国”],
#{:title=>“P和P”,:by=>“Jane”,:cats=>[“道德”、“小说”、“英国”],
#{:title=>“Searchin'”,:by=>“Chad”,:cats=>[“非小说”、“道德”、“全球定位系统”]},
#{:title=>“疯狂的本”、:by=>“沃尔特”、:cats=>[“非小说”、“喜剧”、“爸爸”]}]
库。每个带有_对象({})do | g,h的|
title=g[:title]
g[:猫]。每只{| c |(h[c]| |=[]){“喜剧”=>[“搭车指南”,“疯狂本”],
#“小说”=>[“挂接指南”,“P和P”],
#“英国”=>[“挂接装置指南”,“P和P”],
#“道德”=>[“P和P”,“搜索],
#“非小说”=>[“搜索”,“疯狂本”],
#“gps”=>[“搜索””,
#“爸爸”=>[“疯狂的本”]}
这是其他答案的一个细微变化
library = [
{title: "Hitch Guide", by: "Doug", cats: ["comedy", "fiction", "british"]},
{title: "P and P", by: "Jane", cats: ["morality", "fiction", "british"]},
{title: "Searchin'", by: "Chad", cats: ["non-fiction", "morality", "gps"]},
{title: "Crazy Ben", by: "Walt", cats: ["non-fiction", "comedy", "dads"]}
]
# => [{:title=>"Hitch Guide", :by=>"Doug", :cats=>["comedy", "fiction", "british"]},
# {:title=>"P and P", :by=>"Jane", :cats=>["morality", "fiction", "british"]},
# {:title=>"Searchin'", :by=>"Chad", :cats=>["non-fiction", "morality", "gps"]},
# {:title=>"Crazy Ben", :by=>"Walt", :cats=>["non-fiction", "comedy", "dads"]}]
library.each_with_object({}) do |g,h|
title = g[:title]
g[:cats].each { |c| (h[c] ||= []) << title }
end
#=> {"comedy"=>["Hitch Guide", "Crazy Ben"],
# "fiction"=>["Hitch Guide", "P and P"],
# "british"=>["Hitch Guide", "P and P"],
# "morality"=>["P and P", "Searchin'"],
# "non-fiction"=>["Searchin'", "Crazy Ben"],
# "gps"=>["Searchin'"],
# "dads"=>["Crazy Ben"]}
库=[
{标题:“搭便车指南”,作者:“道格”,猫:[“喜剧”、“小说”、“英国”]},
{标题:“P和P”,作者:“简”,猫:[“道德”、“小说”、“英国”]},
{标题:“搜索”,作者:“乍得”,猫:[“非小说”、“道德”、“全球定位系统”]},
{标题:“疯狂的本”,作者:“沃尔特”,猫:[“非小说”、“喜剧”、“爸爸”]}
]
#=>[{:title=>“搭便车指南”、:by=>“道格”、:cats=>[“喜剧”、“小说”、“英国”],
#{:title=>“P和P”,:by=>“Jane”,:cats=>[“道德”、“小说”、“英国”],
#{:title=>“Searchin'”,:by=>“Chad”,:cats=>[“非小说”、“道德”、“全球定位系统”]},
#{:title=>“疯狂的本”、:by=>“沃尔特”、:cats=>[“非小说”、“喜剧”、“爸爸”]}]
库。每个带有_对象({})do | g,h的|
title=g[:title]
g[:猫]。每只{| c |(h[c]| |=[]){“喜剧”=>[“搭车指南”,“疯狂本”],
#“小说”=>[“挂接指南”,“P和P”],
#“英国”=>[“挂接装置指南”,“P和P”],
#“道德”=>[“P和P”,“搜索],
#“非小说”=>[“搜索”,“疯狂本”],
#“gps”=>[“搜索””,
#“爸爸”=>[“疯狂的本”]}
这是我通常的做法,我认为这是最简单的方法,尽管上面看到的每个带有对象的技巧也很简洁
new_hash = {}
library.each do |hash|
hash["categories"].each do |category|
new_hash[category] ||= []
new_hash[category] << hash["title"]
end
end
new_hash={}
library.each do|hash|
散列[“类别”]。每个都做|类别|
新的_散列[类别]| |=[]
new_hash[category]这是我通常的做法,我认为这是最简单的方法,尽管上面看到的每个_with_object技巧也很简洁
new_hash = {}
library.each do |hash|
hash["categories"].each do |category|
new_hash[category] ||= []
new_hash[category] << hash["title"]
end
end
new_hash={}
library.each do|hash|
散列[“类别”]。每个都做|类别|
新的_散列[类别]| |=[]
新的[category]您需要澄清(通过编辑)您所说的“…以类别作为元素…”是什么意思。首先,您指的是“键”而不是“元素”。您将看到并非所有答案都以相同的方式进行解释。到目前为止,有一个答案假设“categories”是与键关联的值“categories”
在库
的元素(散列)中;有两个答案假设“categories”是库
元素中“categories”的一个或多个值中包含的字符串(“喜剧”、“小说”、“英国”、“道德”、“社会”等)。我猜您是有意进行后一种解释的。您需要澄清(编辑)您所说的“…以类别作为元素…”是什么意思?首先,您指的是“键”而不是“元素”。您将看到并非所有答案都以相同的方式解释。到目前为止,有一个答案假设“类别”是与元素(哈希)中的键“类别”
关联的值对于库
;两个答案假设“categories”是库
元素(“喜剧”、“小说”、“英国”、“道德”、“社会”)中“categories”的一个或多个值中包含的字符串