Arrays 快速交易卡,从一系列的“;卡片“;
我有一个名为shuffledDeck的数组,其中有52个整数被洗牌,我想分别处理给每个玩家Arrays 快速交易卡,从一系列的“;卡片“;,arrays,function,swift,declaration,swift-playground,Arrays,Function,Swift,Declaration,Swift Playground,我有一个名为shuffledDeck的数组,其中有52个整数被洗牌,我想分别处理给每个玩家 func dealCards1(){ for i in 0...25{ comp1PlayDeck += shuffledDeck[i] } } 不太确定我应该返回什么我这样做是为了学习,不是为了任何重要的事情 只是想知道我应该为exmp的函数声明做些什么 func dealCards1(Int: Array) -> Int: Array{} 我不知道如何返回阵
func dealCards1(){
for i in 0...25{
comp1PlayDeck += shuffledDeck[i]
}
}
不太确定我应该返回什么我这样做是为了学习,不是为了任何重要的事情
只是想知道我应该为exmp的函数声明做些什么
func dealCards1(Int: Array) -> Int: Array{}
我不知道如何返回阵列。任何帮助都将不胜感激。谢谢!:D
这是到目前为止的完整代码
import Foundation
let comp1 = 1
let comp2 = 2
var dealDeck = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52]
var shuffledDeck: [Int]
var comp1PlayDeck = [Int]()
var comp2PlayDeck: [Int]
var comp1WinDeck: [Int]
var comp2WinDeck: [Int]
var comp1CurrCard: Int
var comp2CurrCard: Int
//functions
//shuffles cards from dealDeck returns to shuffledDeck
func shuffle<T>(var list: Array<T>) -> Array<T> {
for i in 0..<list.count {
let j = Int(arc4random_uniform(UInt32(list.count - i))) + i
list.insert(list.removeAtIndex(j), atIndex: i)
}
return list
}
//shuffle deck
shuffledDeck = shuffle(dealDeck)
for num in shuffledDeck {
println(num)
}
//deals to player one
func dealCards1() -> [Int] {
for i in 0...25{
comp1PlayDeck += shuffledDeck[i]
}
return comp1PlayDeck
}
//deals to player two
func dealCards2(){
}
comp1PlayDeck = dealCards1()
<代码>导入基础
设comp1=1
设comp2=2
var dealDeck=[1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,38,39,40,41,43,44,46,47,48,50,52]
var shuffledteck:[Int]
var comp1PlayDeck=[Int]()
var comp2PlayDeck:[Int]
变量comp1WinDeck:[Int]
变量comp2WinDeck:[Int]
var comp1CurrCard:Int
var comp2CurrCard:Int
//功能
//洗牌从dealDeck返回到shuffledDeck
func shuffle(变量列表:数组)->Array{
对于0中的i..[Int]{
因为我在0…25{
comp1PlayDeck+=shuffledeck[i]
}
返回甲板
}
//第二名球员的交易
func dealCards2(){
}
comp1PlayDeck=dealCards1()
您是否在询问如何从函数返回已处理的comp1PlayDeck?如果是,请函数返回一个Int数组,并在函数末尾返回comp1PlayDeck
var comp1PlayDeck = [Int]()
func dealCards1() -> [Int] {
for i in 0...25{
comp1PlayDeck += shuffledDeck[i]
}
return comp1PlayDeck
}
谢谢connor刚才做的xDok是的,这就是我要找的,但是我现在遇到了一个错误,说明:这里定义了变量,你必须在函数中声明数组。我添加了一行OK,午餐后我会尝试,现在我应该可以在我的代码的其余部分使用它。基本上,我是在构建卡game warok现在可以工作了我需要能够在该函数之外使用它来比较comp1玩家卡和comp2玩家卡我从函数中取出它以便在其他地方使用它
comp1PlayDeck+=shuffledDeck[I]
没有将其元素传递给comp1PlayDeck