Asp.net mvc 获取Orchard CMS中PartialView的链接_Asp.net Mvc_Razor_Content Management System_Orchardcms_Asp.net Mvc Partialview

Asp.net mvc 获取Orchard CMS中PartialView的链接

asp.net-mvc razor content-management-system orchardcms

Asp.net mvc 获取Orchard CMS中PartialView的链接,asp.net-mvc,razor,content-management-system,orchardcms,asp.net-mvc-partialview,Asp.net Mvc,Razor,Content Management System,Orchardcms,Asp.net Mvc Partialview,我想将RazorView渲染为字符串，但在Orchard CMS中，我不知道如何获取部分视图的链接以获取字符串 public string RenderRazorViewToString(string viewName, object model) { ViewData.Model = model; using (var sw = new StringWriter()) { v

我想将RazorView渲染为字符串，但在Orchard CMS中，我不知道如何获取部分视图的链接以获取字符串

public string RenderRazorViewToString(string viewName, object model)
        {
            ViewData.Model = model;
            using (var sw = new StringWriter())
            {
                var viewResult = ViewEngines.Engines.FindPartialView(ControllerContext, viewName);
                var viewContext = new ViewContext(ControllerContext, viewResult.View, ViewData, TempData, sw);
                viewResult.View.Render(viewContext, sw);
                viewResult.ViewEngine.ReleaseView(ControllerContext, viewResult.View);
                return sw.GetStringBuilder().ToString();
            }
        }

如果在另一个MVC项目中，而不是在Orchard中，则代码正常：

string result = RenderRazorViewToString("~/Views/Home/PartialViewEmail.cshtml", null);

但在Orchard CMS，它不知道在哪里可以看到这种局部视图

我该怎么办

非常感谢

我已经解决了那个问题。它非常简单，如下所示

PartialViewResult path = PartialView("PartialViewEmail");
string tmp = path.ViewName;
string result = RenderRazorViewToString(tmp, null);

我已经解决了那个问题。它非常简单，如下所示

PartialViewResult path = PartialView("PartialViewEmail");
string tmp = path.ViewName;
string result = RenderRazorViewToString(tmp, null);

然而，更好的解决方案是采用Orchard的方式，使用形状。如果您这样做：

@Display.ViewEmail(SomeParameter: 42, SomeOtherParameter: "foo")

然后在主题中的

/Views

下创建一个名为

viewmail.cshtml

的文件，如果需要，可以引用作为

模型的属性传入的参数。调用Display
将导致呈现viewmail
形状。
更好的解决方案是采用Orchard方式，使用形状。如果您这样做：
@Display.ViewEmail(SomeParameter: 42, SomeOtherParameter: "foo")

然后在主题中的/Views
下创建一个名为viewmail.cshtml
的文件，如果需要，可以引用作为模型的属性传入的参数。调用Display
将导致呈现viewmail
形状。
我选择了如下扩展方法：
public static class ViewExtensions
{
    public static string RenderToString(this PartialViewResult partialView)
    {
        var httpContext = HttpContext.Current;

        if (httpContext == null)
        {
            throw new NotSupportedException("An HTTP context is required to render the partial view to a string");
        }

        var controllerName = httpContext.Request.RequestContext.RouteData.Values["controller"].ToString();

        var controller = (ControllerBase)ControllerBuilder.Current.GetControllerFactory().CreateController(httpContext.Request.RequestContext, controllerName);

        var controllerContext = new ControllerContext(httpContext.Request.RequestContext, controller);

        var view = ViewEngines.Engines.FindPartialView(controllerContext, partialView.ViewName).View;

        var sb = new StringBuilder();

        using (var sw = new StringWriter(sb))
        {
            using (var tw = new HtmlTextWriter(sw))
            {
                view.Render(new ViewContext(controllerContext, view, partialView.ViewData, partialView.TempData, tw), tw);
            }
        }

        return sb.ToString();
    }
}

var html = PartialView("SomeView").RenderToString();

var path = ((BuildManagerCompiledView)view).ViewPath; // Will be something like "~/Views/Shared/SomeView.cshtml"

它允许我执行以下操作：
public static class ViewExtensions
{
    public static string RenderToString(this PartialViewResult partialView)
    {
        var httpContext = HttpContext.Current;

        if (httpContext == null)
        {
            throw new NotSupportedException("An HTTP context is required to render the partial view to a string");
        }

        var controllerName = httpContext.Request.RequestContext.RouteData.Values["controller"].ToString();

        var controller = (ControllerBase)ControllerBuilder.Current.GetControllerFactory().CreateController(httpContext.Request.RequestContext, controllerName);

        var controllerContext = new ControllerContext(httpContext.Request.RequestContext, controller);

        var view = ViewEngines.Engines.FindPartialView(controllerContext, partialView.ViewName).View;

        var sb = new StringBuilder();

        using (var sw = new StringWriter(sb))
        {
            using (var tw = new HtmlTextWriter(sw))
            {
                view.Render(new ViewContext(controllerContext, view, partialView.ViewData, partialView.TempData, tw), tw);
            }
        }

        return sb.ToString();
    }
}

var html = PartialView("SomeView").RenderToString();

var path = ((BuildManagerCompiledView)view).ViewPath; // Will be something like "~/Views/Shared/SomeView.cshtml"

如果出于某种原因，我仍然希望获得视图的完整路径，我可以执行以下操作：
public static class ViewExtensions
{
    public static string RenderToString(this PartialViewResult partialView)
    {
        var httpContext = HttpContext.Current;

        if (httpContext == null)
        {
            throw new NotSupportedException("An HTTP context is required to render the partial view to a string");
        }

        var controllerName = httpContext.Request.RequestContext.RouteData.Values["controller"].ToString();

        var controller = (ControllerBase)ControllerBuilder.Current.GetControllerFactory().CreateController(httpContext.Request.RequestContext, controllerName);

        var controllerContext = new ControllerContext(httpContext.Request.RequestContext, controller);

        var view = ViewEngines.Engines.FindPartialView(controllerContext, partialView.ViewName).View;

        var sb = new StringBuilder();

        using (var sw = new StringWriter(sb))
        {
            using (var tw = new HtmlTextWriter(sw))
            {
                view.Render(new ViewContext(controllerContext, view, partialView.ViewData, partialView.TempData, tw), tw);
            }
        }

        return sb.ToString();
    }
}

var html = PartialView("SomeView").RenderToString();

var path = ((BuildManagerCompiledView)view).ViewPath; // Will be something like "~/Views/Shared/SomeView.cshtml"

我选择了如下扩展方法：
public static class ViewExtensions
{
    public static string RenderToString(this PartialViewResult partialView)
    {
        var httpContext = HttpContext.Current;

        if (httpContext == null)
        {
            throw new NotSupportedException("An HTTP context is required to render the partial view to a string");
        }

        var controllerName = httpContext.Request.RequestContext.RouteData.Values["controller"].ToString();

        var controller = (ControllerBase)ControllerBuilder.Current.GetControllerFactory().CreateController(httpContext.Request.RequestContext, controllerName);

        var controllerContext = new ControllerContext(httpContext.Request.RequestContext, controller);

        var view = ViewEngines.Engines.FindPartialView(controllerContext, partialView.ViewName).View;

        var sb = new StringBuilder();

        using (var sw = new StringWriter(sb))
        {
            using (var tw = new HtmlTextWriter(sw))
            {
                view.Render(new ViewContext(controllerContext, view, partialView.ViewData, partialView.TempData, tw), tw);
            }
        }

        return sb.ToString();
    }
}

var html = PartialView("SomeView").RenderToString();

var path = ((BuildManagerCompiledView)view).ViewPath; // Will be something like "~/Views/Shared/SomeView.cshtml"

它允许我执行以下操作：
public static class ViewExtensions
{
    public static string RenderToString(this PartialViewResult partialView)
    {
        var httpContext = HttpContext.Current;

        if (httpContext == null)
        {
            throw new NotSupportedException("An HTTP context is required to render the partial view to a string");
        }

        var controllerName = httpContext.Request.RequestContext.RouteData.Values["controller"].ToString();

        var controller = (ControllerBase)ControllerBuilder.Current.GetControllerFactory().CreateController(httpContext.Request.RequestContext, controllerName);

        var controllerContext = new ControllerContext(httpContext.Request.RequestContext, controller);

        var view = ViewEngines.Engines.FindPartialView(controllerContext, partialView.ViewName).View;

        var sb = new StringBuilder();

        using (var sw = new StringWriter(sb))
        {
            using (var tw = new HtmlTextWriter(sw))
            {
                view.Render(new ViewContext(controllerContext, view, partialView.ViewData, partialView.TempData, tw), tw);
            }
        }

        return sb.ToString();
    }
}

var html = PartialView("SomeView").RenderToString();

var path = ((BuildManagerCompiledView)view).ViewPath; // Will be something like "~/Views/Shared/SomeView.cshtml"

如果出于某种原因，我仍然希望获得视图的完整路径，我可以执行以下操作：
public static class ViewExtensions
{
    public static string RenderToString(this PartialViewResult partialView)
    {
        var httpContext = HttpContext.Current;

        if (httpContext == null)
        {
            throw new NotSupportedException("An HTTP context is required to render the partial view to a string");
        }

        var controllerName = httpContext.Request.RequestContext.RouteData.Values["controller"].ToString();

        var controller = (ControllerBase)ControllerBuilder.Current.GetControllerFactory().CreateController(httpContext.Request.RequestContext, controllerName);

        var controllerContext = new ControllerContext(httpContext.Request.RequestContext, controller);

        var view = ViewEngines.Engines.FindPartialView(controllerContext, partialView.ViewName).View;

        var sb = new StringBuilder();

        using (var sw = new StringWriter(sb))
        {
            using (var tw = new HtmlTextWriter(sw))
            {
                view.Render(new ViewContext(controllerContext, view, partialView.ViewData, partialView.TempData, tw), tw);
            }
        }

        return sb.ToString();
    }
}

var html = PartialView("SomeView").RenderToString();

var path = ((BuildManagerCompiledView)view).ViewPath; // Will be something like "~/Views/Shared/SomeView.cshtml"