Asp.net mvc 在MVC中获取服务器端错误的实例上，无法在模式中显示部分视图
从过去的三天开始，我在这方面一直很努力。我有一个_布局页面，在该页面中，单击Login按钮，我会在一个模式div中加载一个Login部分视图。当我提交时，如果有任何客户端验证可以正常工作，表单在给出正确数据之前不会提交发生服务器端验证时出现问题。如果凭据无效，它将重定向到同一页面，但不会显示模式。当我再次单击登录按钮时，无效凭证错误消息将显示在模式中。我想知道，通过我正在尝试的方式，这是否是可能的，或者是否有其他方法来实现这一点 这是布局页面的一部分：Asp.net mvc 在MVC中获取服务器端错误的实例上，无法在模式中显示部分视图,asp.net-mvc,asp.net-mvc-partialview,server-side-validation,Asp.net Mvc,Asp.net Mvc Partialview,Server Side Validation,从过去的三天开始，我在这方面一直很努力。我有一个_布局页面，在该页面中，单击Login按钮，我会在一个模式div中加载一个Login部分视图。当我提交时，如果有任何客户端验证可以正常工作，表单在给出正确数据之前不会提交发生服务器端验证时出现问题。如果凭据无效，它将重定向到同一页面，但不会显示模式。当我再次单击登录按钮时，无效凭证错误消息将显示在模式中。我想知道，通过我正在尝试的方式，这是否是可能的，或者是否有其他方法来实现这一点 这是布局页面的一部分： <a class="btn btn-
<a class="btn btn-style btn-success btn-lg btn-wid" data-target="#modal" data-toggle="modal" id="flogin"> Login </a>
@model Sample.Models.LoginModel
@section Validation {
@Scripts.Render("~/bundles/jqueryval")
}
<section id="Login">
@using (Html.BeginForm("Login", "Home", FormMethod.Post, new { enctype = "multipart/form-data", id = "LoginForm", ReturnUrl = ViewBag.ReturnUrl }))
{
<div class="modal-content wrap col-md-4 col-xs-12 col-sm-12 col-md-offset-4">
@Html.AntiForgeryToken()
<div class="row">
<button type="button" class="close" id="btnLoginModalClose" style="margin-top:-15px" data-dismiss="modal" aria-hidden="true">×</button>
</div>
<div class="row-fluid">
<div id="LoginDialog" class="col-md-12">
<div class="modal-header">
<h3 id="login" class="modal-title">
Freshers Login
</h3>
<div class="ui-state-error-text">
@if (TempData["ModelState"] != null)
{
@TempData["ModelState"]
}
</div>
</div>
<div class="modal-body">
<div class="form-group">
<span class="ico-email"></span>
@Html.TextBoxFor(m => m.UserName, new { id = "floginEmail", placeholder = "Email", type = "email", @class = "input-lg ipt ip-email" })
<div class="text-danger">
@Html.ValidationMessageFor(model => model.UserName)
</div>
</div>
<div class="form-group">
<span class="ico-pwd"></span>
@Html.TextBoxFor(m => m.Password, new { id = "floginPassword", placeholder = "Password", type = "password", @class = "input-lg ipt ip-pwd" })
<a href="#" id="loginpswdshow" onclick="showhide($(this));"><span style="position:relative" id="sploginpswdshow" class="glyphicon glyphicon-eye-open show"></span></a>
<div class="text-danger">
@Html.ValidationMessageFor(model => model.Password)
</div>
</div>
<div class="form-group">
<div class="input-group">
<span class="input-group-addon">
@Html.CheckBoxFor(m => m.RememberMe, new { id = "chkRemember", type = "checkbox", @class = "checkbox" })
</span>
@Html.LabelFor(m => m.RememberMe, new { @class = "form-control" })
</div><!-- /input-group -->
</div>
</div>
<div class="modal-footer" style="margin-top:14px">
<input type="submit" id="btnLogin" name="login" style="margin-top:-5px" class="btn btn-primary pull-left btn-flogin" value="Log-in" />
<div class="row-fluid">
<a class="text-center" style="font-size:medium" onclick="fresherForgotClick();" id="lnkForgot" href="#">Forgot password?</a>
</div>
</div>
<span class="text-info"><strong>Do not have an Account? <a class="btn alert-danger" id="btnCreateAccount">Click here to Create one!</a></strong></span>
</div>
</div>
</div>
}
</section>
请让我知道是否可以通过以下方式实现此目的。您的工作流程可能应该遵循以下方式：
public ActionResult Login(Models.FreshersModel model, string returnUrl)
{
bool success = false;
string message = "User name or password is incorrect.";
if (ModelState.IsValid)
{
success = model.IsValid(model.UserName,model.Password);
if(success)
{
message = string.Empty;
FormsAuthentication.SetAuthCookie(model.UserName, model.RememberMe);
}
}
return Json(new { success = success, message = message });
}
<div id="LoginDialog" class="modal hide">
<div class="modal-header">
<h3 id="login" class="modal-title">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
Freshers Login
</h3>
</div>
<div class="modal-body">
@using (Html.BeginForm("Login", "Home", new { returnUrl = ViewBag.ReturnUrl }, FormMethod.Post, new { id = "LoginForm", role="form" }))
{
@Html.AntiForgeryToken()
<div id="errors" class="ui-state-error-text">
</div>
<div class="form-group">
<span class="ico-email"></span>
@Html.TextBoxFor(m => m.UserName, new { id = "floginEmail", placeholder = "Email", type = "email", @class = "input-lg ipt ip-email" })
<div class="text-danger">
@Html.ValidationMessageFor(model => model.UserName)
</div>
</div>
<div class="form-group">
<span class="ico-pwd"></span>
@Html.PasswordFor(m => m.Password, new { id = "floginPassword", placeholder = "Password", @class = "input-lg ipt ip-pwd" })
<div class="text-danger">
@Html.ValidationMessageFor(model => model.Password)
</div>
</div>
<div class="form-group">
<div class="input-group">
<span class="input-group-addon">
@Html.CheckBoxFor(m => m.RememberMe, new { id = "chkRemember", @class = "checkbox" })
</span>
@Html.LabelFor(m => m.RememberMe, new { @class = "form-control" })
</div><!-- /input-group -->
</div>
}
</div>
<div class="modal-footer">
<a href="#" class="btn">Close</a>
<button type="button" class="btn btn-primary" id="btnLogin">Login</button>
</div>
</div>
我省略了一些部分，比如启动模式，但这应该可以让您开始了。所以您是说，我需要使用JsonResult类型，而不是ActionResult。如果您将流程修改为使用ajax，则可以。您可以将返回类型保留为ActionResult，因为JsonResult隐式转换。您建议使用哪种类型。。。？我的意思是，它是安全的，并且不会降低性能。不管怎样，它都不安全。性能是相对的。我将更新答案以显示我的建议。
public ActionResult Login(Models.FreshersModel model, string returnUrl)
{
bool success = false;
string message = "User name or password is incorrect.";
if (ModelState.IsValid)
{
success = model.IsValid(model.UserName,model.Password);
if(success)
{
message = string.Empty;
FormsAuthentication.SetAuthCookie(model.UserName, model.RememberMe);
}
}
return Json(new { success = success, message = message });
}
<div id="LoginDialog" class="modal hide">
<div class="modal-header">
<h3 id="login" class="modal-title">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
Freshers Login
</h3>
</div>
<div class="modal-body">
@using (Html.BeginForm("Login", "Home", new { returnUrl = ViewBag.ReturnUrl }, FormMethod.Post, new { id = "LoginForm", role="form" }))
{
@Html.AntiForgeryToken()
<div id="errors" class="ui-state-error-text">
</div>
<div class="form-group">
<span class="ico-email"></span>
@Html.TextBoxFor(m => m.UserName, new { id = "floginEmail", placeholder = "Email", type = "email", @class = "input-lg ipt ip-email" })
<div class="text-danger">
@Html.ValidationMessageFor(model => model.UserName)
</div>
</div>
<div class="form-group">
<span class="ico-pwd"></span>
@Html.PasswordFor(m => m.Password, new { id = "floginPassword", placeholder = "Password", @class = "input-lg ipt ip-pwd" })
<div class="text-danger">
@Html.ValidationMessageFor(model => model.Password)
</div>
</div>
<div class="form-group">
<div class="input-group">
<span class="input-group-addon">
@Html.CheckBoxFor(m => m.RememberMe, new { id = "chkRemember", @class = "checkbox" })
</span>
@Html.LabelFor(m => m.RememberMe, new { @class = "form-control" })
</div><!-- /input-group -->
</div>
}
</div>
<div class="modal-footer">
<a href="#" class="btn">Close</a>
<button type="button" class="btn btn-primary" id="btnLogin">Login</button>
</div>
</div>
$(function(){
$(document)
.on('submit', '#LoginForm', function(e) {
e.preventDefault(); /* we're taking over the default behaviour */
var url = $(this).attr('action');
var formData = $(this).serialize();
$.post(url, formData)
.fail(function(jqxhr, status, error){
$('#errors').html('An error occurred. Please try again.');
})
.done(function(response, status, jqxhr){
if(response.success) {
window.location.redirect('/');
}
else {
$('#errors').html(response.message);
}
});
})
.on('click', '#btnSubmit', function(e) {
e.preventDefault();
$('#LoginForm').trigger('submit');
});
});