Automation Apple脚本，用于聆听是或否的答案

事实上，我已经有了这个脚本（作为一个完全的初学者，我感到很惊讶），但我只是想确保这个脚本没有多余的代码，我不需要。或者如果有更好的方法，请评论！我最终尝试创建一系列语音命令

tell application "SpeechRecognitionServer"
set l1 to {"yes", "sure", "yes please", "open mail"}
set l2 to {"no", "no thanks", "not now"}
set no_answer to {"no", "no thanks", "not now"}

set answer to listen for l1 & l2 with prompt "Would you like me to open your email"
l1 contains answer
l2 contains no_answer


end tell

if l1 contains answer then
say "yes answer"

else if l2 contains no_answer then
say "no answer"
end if

end

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提前谢谢

您应该只在tell块中包含属于您正在“讲述”的应用程序的命令。在块外建立列表

set l1 to {"yes", "sure", "yes please", "open mail"}
set l2 to {"no", "no thanks", "not now"}

这没有任何作用

l1 contains answer
l2 contains no_answer

l2将始终不包含任何答案，因为它们是两个静态列表

else if l2 contains no_answer

请尝试以下方法：

set l1 to {"yes", "sure", "yes please", "open mail"}
set l2 to {"no", "no thanks", "not now"}

activate application "SpeechRecognitionServer"

try
    tell application "SpeechRecognitionServer" to set answer to listen for l1 & l2 with prompt "Would you like me to open your email" giving up after 20
on error number -128
    say "User did not respond"
    error number -128
end try

if l1 contains answer then
    say "yes answer"

else if l2 contains answer then
    say "no answer"
end if