awk用引号连接csv列

我想连接csv文件的两列。我对csv的引用有一些问题

"column one","column two","column three"
"A","1","A1"
"B","2","B2"
"C","3","C3"

我使用以下命令行：

awk -F, '{$2=$3" - "$x;for(i=1;i<=NF;i++)if(i!=x)f=f?f FS $i:$i;print f;f=""}' x=3 file.csv

---

我想删除两列“3**”-“**C3”的内部引号

Awk

解决方案：

awk 'BEGIN{ FS=OFS="\042,\042" }{ $2=$2" - "$3; NF=2 }1' file.csv

输出：

"A","1 - A1"
"B","2 - B2"
"C","3 - C3"

Gnu sed： 测试：

kent$  cat f
"A","1","A1"
"B","2","B2"
"C","3","C3"

kent$  sed 's/","/ - /2' f
"A","1 - A1"
"B","2 - B2"
"C","3 - C3"

---

使用GNU

awk

$ awk -F, -v OFS=, 'NR==1{NF--} {print gensub(/","/," - ",2)}' file

"column one","column two"
"A","1 - A1"
"B","2 - B2"
"C","3 - C3"

---

对于第一行，删除最后一个字段。否则，用连字符替换带引号的逗号。

预期的输出是什么？谢谢Kent。记住你的解决方案，但我想用AWK。

kent$  cat f
"A","1","A1"
"B","2","B2"
"C","3","C3"

kent$  sed 's/","/ - /2' f
"A","1 - A1"
"B","2 - B2"
"C","3 - C3"

$ awk -F, -v OFS=, 'NR==1{NF--} {print gensub(/","/," - ",2)}' file

"column one","column two"
"A","1 - A1"
"B","2 - B2"
"C","3 - C3"