Azure cosmosdb 仅从条件返回子项的子集
是否可以对子项执行条件查询?我正在尝试返回所有组,以及计数大于0的所有子组(以及这些子组)。请注意,如果计数大于0,子组也需要返回子组 文件:Azure cosmosdb 仅从条件返回子项的子集,azure-cosmosdb,azure-cosmosdb-sqlapi,Azure Cosmosdb,Azure Cosmosdb Sqlapi,是否可以对子项执行条件查询?我正在尝试返回所有组,以及计数大于0的所有子组(以及这些子组)。请注意,如果计数大于0,子组也需要返回子组 文件: { "id": 1, "name": "name1", "groups": [ { "id": 1, "name": "name1", "subGroups": [ { "id": 1, "name": "name1", "
{
"id": 1,
"name": "name1",
"groups": [
{
"id": 1,
"name": "name1",
"subGroups": [
{
"id": 1,
"name": "name1",
"count": 4,
"assests": [ "asset1", "asset2" ]
},
{
"id": 2,
"name": "name2",
"count": 0,
"assests": [ "asset1", "asset2" ]
}
]
},
{
"id": 2,
"name": "name2",
"subGroups": [
{
"id": 1,
"name": "name1",
"count": 4,
"assests": [ "asset1", "asset2" ]
},
{
"id": 2,
"name": "name2",
"count": 0,
"assests": [ "asset1", "asset2" ]
}
]
}
]
}
通缉结果:
{
"id": 1,
"name": "name1",
"groups": [
{
"id": 1,
"name": "name1",
"subGroups": [
{
"id": 1,
"name": "name1",
"count": 4,
"assests": [ "asset1", "asset2" ]
}
]
},
{
"id": 2,
"name": "name2",
"subGroups": [
{
"id": 1,
"name": "name1",
"count": 2,
"assests": [ "asset1", "asset2" ]
}
]
}
]
}
我试着通过加入来做,但还没有找到一种可以跳过某些子组而不跳过其他子组的方法。欢迎所有建议。我建议您使用来实现您的期望结果。请参考我的示例代码:
function sample() {
var collection = getContext().getCollection();
var isAccepted = collection.queryDocuments(
collection.getSelfLink(),
'SELECT * FROM root r',
function (err, feed, options) {
if (err) throw err;
if (!feed || !feed.length) {
var response = getContext().getResponse();
response.setBody('no docs found');
}
else {
var returnArray = [];
for(var i=0 ;i<feed.length;i++){
var groupsArray = feed[i].groups;
var map ={};
var groups = [];
for(var j=0 ;j<groupsArray.length; j++){
var map1 = {};
map1["id"] = groupsArray[j].id;
map1["name"] = groupsArray[j].name;
var subGroupsArray = groupsArray[j].subGroups;
var sub = [];
for(var k=0 ;k<subGroupsArray.length;k++){
if(subGroupsArray[k].count > 0)
sub.push(subGroupsArray[k]);
}
map1["subGroups"] = sub;
groups.push(map1);
}
map["id"] = feed[i].id;
map["name"] = feed[i].name;
map["groups"] = groups;
returnArray.push(map);
}
var response = getContext().getResponse();
response.setBody(returnArray);
}
});
if (!isAccepted) throw new Error('The query was not accepted by the server.');
}
这是我担心的。它非常针对开发人员,而不是DBA。但是谢谢你的回答,非常感谢。我等了一会儿,看看是否有人有查询方法。@ThomasSegato当然,我也会尝试深入研究sql。@ThomasSegato也许你可以在sql中使用udf函数。但这是不是同样的方法?如果您不使用查询,而是使用更多的开发方法,那么您的解决方案似乎就是我们所说的方向。更多的功能将适当地来,但现在我会去你的方式。谢谢你的帮助,非常感谢!
function test(groupsArray){
var map ={};
var groups = [];
for(var j=0 ;j<groupsArray.length; j++){
var map1 = {};
map1["id"] = groupsArray[j].id;
map1["name"] = groupsArray[j].name;
var subGroupsArray = groupsArray[j].subGroups;
var sub = [];
for(var k=0 ;k<subGroupsArray.length;k++){
if(subGroupsArray[k].count > 0)
sub.push(subGroupsArray[k]);
}
map1["subGroups"] = sub;
groups.push(map1);
}
return groups;
}
SELECT c.id,c.name,udf.test(c.groups) as groups FROM c