无法通过asyncio使用bash命令
我正在尝试生成一个简单的命令,我可以在discord中调用该命令,以查看目录中有多少个文件,但由于某些原因,我的代码在运行该命令时不断出现以下错误:无法通过asyncio使用bash命令,bash,python-3.x,python-asyncio,Bash,Python 3.x,Python Asyncio,我正在尝试生成一个简单的命令,我可以在discord中调用该命令,以查看目录中有多少个文件,但由于某些原因,我的代码在运行该命令时不断出现以下错误: `Traceback (most recent call last): File "/home/pi/MusicToaster/musicbot/bot.py", line 1995, in on_message response = await handler(**handler_kwargs) File "/home/pi/M
`Traceback (most recent call last):
File "/home/pi/MusicToaster/musicbot/bot.py", line 1995, in on_message
response = await handler(**handler_kwargs)
File "/home/pi/MusicToaster/musicbot/bot.py", line 1822, in cmd_audiocache
stdout=asyncio.subprocess.PIPE)
File "/usr/local/lib/python3.5/asyncio/subprocess.py", line 212, in create_subprocess_exec
stderr=stderr, **kwds)
File "/usr/local/lib/python3.5/asyncio/base_events.py", line 970, in subprocess_exec
bufsize, **kwargs)
File "/usr/local/lib/python3.5/asyncio/unix_events.py", line 184, in _make_subprocess_transport
**kwargs)
File "/usr/local/lib/python3.5/asyncio/base_subprocess.py", line 40, in __init__
stderr=stderr, bufsize=bufsize, **kwargs)
File "/usr/local/lib/python3.5/asyncio/unix_events.py", line 635, in _start
universal_newlines=False, bufsize=bufsize, **kwargs)
File "/usr/local/lib/python3.5/subprocess.py", line 950, in __init__
restore_signals, start_new_session)
File "/usr/local/lib/python3.5/subprocess.py", line 1540, in _execute_child
raise child_exception_type(errno_num, err_msg)
FileNotFoundError: [Errno 2] No such file or directory: 'find /home/pi/MusicToaster/audio_cache -type f | wc -l'`
我检查了正在运行的命令,我无法找到它出错的原因,当我手动键入时,我没有问题:
该值增加了,因为在我拍摄该屏幕截图时,写入该文件夹的bot正在运行
以下是该命令的代码:
async def cmd_audiocache(self, channel):
await self.safe_send_message(channel, "hang on ill check :thinking:")
process = await asyncio.create_subprocess_exec(
'find /home/pi/MusicToaster/audio_cache -type f | wc -l',
stdout=asyncio.subprocess.PIPE)
stdout, stderr = await process.communicate()
file_count = stdout.decode().strip()
file_count = str(file_count)
file_count = file_count + " songs stored"
await self.safe_send_message(channel, file_count)
process = await asyncio.create_subprocess_exec(
'du /home/pi/MusicToaster/audio_cache -h',
stdout=asyncio.subprocess.PIPE)
stdout, stderr = await process.communicate()
file_size = stdout.decode().strip()
file_size = str(file_size)
file_size = "all songs total to" + file_size
await self.safe_send_message(channel, file_size)
请原谅代码的混乱,我不会整理代码,直到我知道它能工作。注意以下两者之间的区别: 从一个或多个字符串参数[…]创建子流程,其中第一个字符串指定要执行的程序,其余字符串指定程序的参数 以及: 使用平台的“shell”语法从cmd[…]创建子流程 例如:
# Using exec
process = await asyncio.create_subprocess_exec('ls', '-l')
# Using shell
process = await asyncio.create_subprocess_shell('ls -l')
因此,如果我有一个完整的shell命令作为一个长字符串,如何将其发送到
asyncio.create_subprocess_exec()
,以防止shell注入?我尝试了commandString.split()
,但与Popen
不同,subprocess\u exec
不接受列表…@medley56过去,解决方案是使用create\u subprocess\u exec(*cmdList…)
@medley56过去,解决方案是使用shlex.quote()
方法。如果需要调用create\u subprocess\u exec()
,则对字符串调用split()
函数。请在此处阅读更多信息: