Bash 不带分隔符的awk分割字符串
我想使用awk分析以下运行测试的结果/统计文件:Bash 不带分隔符的awk分割字符串,bash,time,awk,split,Bash,Time,Awk,Split,我想使用awk分析以下运行测试的结果/统计文件: $date $time $statname $traffic_rate $val1 $val2 20140909 132920326 stat1 30/sec 40 80 20140909 132950326 stat1 29/sec 60 20 20140909 133020326 stat1 28/sec 70 100 20140909 1330
$date $time $statname $traffic_rate $val1 $val2
20140909 132920326 stat1 30/sec 40 80
20140909 132950326 stat1 29/sec 60 20
20140909 133020326 stat1 28/sec 70 100
20140909 133050326 stat1 0/sec 0 0
20140909 133120326 stat1 0/sec 0 0
20140909 133150326 stat1 30/sec 90 50
$time
的格式为:hhmmsmm
,统计数据以30秒的间隔生成。我需要为每个连续的统计数据取平均值,$traffic\u rate值>='28/秒'。忽略流量率<28/秒的统计数据,并在下一系列>=28/秒的数据中重复该过程,以此类推
我想使用bash脚本,并认为awk将是分析列数据的一个好选择。为了将连续时间戳与$traffic_rate>=28/秒进行比较,我需要将$time与mktime进行转换。但是,由于没有分隔符,我无法拆分$time。有没有一种方法可以像在PHP中那样按字符数进行拆分
样本输出如下所示:
test# $val $val2
1 170/3 200/3
2 90/1 50/1
也就是说,每个连续>=28/秒是一个单独的测试结果,应单独计算
此外,任何其他分析此类模式的建议都将受到赞赏。谢谢。如果
流量率为每30秒,您可以使用平均val1
val2
的短脚本完成所需:
#!/bin/bash
## validate data file input
[ -f "$1" ] || {
printf "\nError: insufficient input. File '%s' not found.\n\n" "${0//\//}"
exit 1
}
declare -i cnt=0 # simple count variable
printf "\n val1 val2\n\n" # print generic header
## read each line in file
while read -r dt tm sn trf v1 v2 || [ -n "$dt" ]; do
trf=${trf%/*} # extract numeric traffic_rate
if [ "$trf" = 30 ]; then # if equal to 30
v1a+=( $v1 ) # add values to v1 array and v2 array
v2a+=( $v2 )
((cnt++))
else
v1s=0 # reset v1 sum and v2 sum
v2s=0
for i in ${v1a[@]}; do v1s=$((v1s+i)); done # calculate v1 sum from v1 array
for i in ${v2a[@]}; do v2s=$((v2s+i)); done # calculate v2 sum from v2 array
if [ $v1s -gt 0 ] && [ $v2s -gt 0 ]; then # if both greater than 0, output
printf " %6s %6s\n" \
$( echo "scale=2; $v1s/$cnt" | bc ) $( echo "scale=2; $v2s/$cnt" | bc )
fi
cnt=0
unset v1a v2a
fi
done <"$1"
## output if array elements remain
if [ ${#v1a[@]} -gt 0 ]; then
v1s=0
v2s=0
for i in ${v1a[@]}; do v1s=$((v1s+i)); done
for i in ${v2a[@]}; do v2s=$((v2s+i)); done
if [ $v1s -gt 0 ] && [ $v2s -gt 0 ]; then
printf " %6s %6s\n" \
$( echo "scale=2; $v1s/$cnt" | bc ) $( echo "scale=2; $v2s/$cnt" | bc )
fi
cnt=0
unset v1a v2a
fi
printf "\n"
exit 0
使用awk
:
awk -v OFS="\t" '
BEGIN { print "test#", "$val", "$val2" }
$4 == "0/sec" && count {
print ++id, val1/count, val2/count
count = val1 = val2 = 0
}
$4+0>=28 && NR>1 {
val1+=$5
val2+=$6
++count
}
END {
print ++id, val1/count, val2/count
}' file
test# $val $val2
1 56.6667 66.6667
2 90 50
您还应该发布您尝试过的内容和预期输出。添加了示例输出
awk -v OFS="\t" '
BEGIN { print "test#", "$val", "$val2" }
$4 == "0/sec" && count {
print ++id, val1/count, val2/count
count = val1 = val2 = 0
}
$4+0>=28 && NR>1 {
val1+=$5
val2+=$6
++count
}
END {
print ++id, val1/count, val2/count
}' file
test# $val $val2
1 56.6667 66.6667
2 90 50