Bash 这里的多行字符串只产生一行

我需要在whiledo循环中处理一个sting数组，计算一个值并在循环外使用它。首先，我编写了以下代码：

git diff-index --cached HEAD | while read -r LINE; do
   ...
done

但是，当然，它不保留内部变量值。然后，根据我在这里找到的建议，我使用了输入重定向：

while read -r LINE; do
...
done <<<$(git diff-index --cached HEAD)

读取-r行时

；做
...
完成您使用的是
您走的是正确的道路，您只需要在
git
生成的输出周围加上引号，以便将其正确地视为单个多行字符串：

while read -r LINE; do
...
done <<< "$(git diff-index --cached HEAD)"

读取-r行时
；做
...
做了相当详细和清楚的回答，它确实帮助了我。谢谢！
while read -r LINE; do
...
done <<< "$(git diff-index --cached HEAD)"

# "one" is passed on stdin, nothing happens
# "two" and "three" are passed as arguments, and echoed to stdout
$ echo <<< one two three
two three

# "one" is passed on stdin, gets printed to stdout
# "two" and "three" are passed as arguments, cat thinks they are filenames
$ cat <<< one two three 
cat: two: No such file or directory
cat: three: No such file or directory

# "one two three" is passed on stdin
# echo is invoked with no arguments and prints a blank line
$ echo <<< "one two three"

# "one two three" is passed on stdin
# cat is invoked with no arguments and prints whatever comes from stdin
$ cat <<< "one two three"
one two three