BASH xdool鼠标单击，重复并停止

我正在尝试使用xdoool将一个简单的无限点击脚本与另一个脚本集成起来，以检测键盘输入；当按下某个键但不确定如何匹配时，结束正在运行的单击脚本

该脚本在xdool确定的屏幕光标点XXX，YYY无限重复地运行

 #!/bin/bash
 while true [ 1 ]; do
 xdotool mousemove XXX YYY click 1 &
 sleep 1.5
 done

下一步，我希望使用如下内容：

#!/bin/bash
if [ -t 0 ]; then stty -echo -icanon -icrnl time 0 min 0; fi
count=0
keypress=''
while [ "x$keypress" = "x" ]; do
let count+=1
echo -ne $count'\r'
keypress="`cat -v`"
done
if [ -t 0 ]; then stty sane; fi
echo "You pressed '$keypress' after $count loop iterations"
echo "Thanks for using this script."
exit 0

我不明白我是怎么看待这个问题的：

 xdotool mousemove XXX YYY click 1 &
 sleep 1.5

在上面的脚本中，BASH混乱和manbash没有帮助，所以任何能提供帮助的人都会很感激。感谢改进（和评论）脚本：

#!/bin/bash

x_pos="0"   # Position of the mouse pointer in X.
y_pos="0"   # Position of the mouse pointer in Y.
delay="1.5" # Delay between clicks.

# Exit if not runs from a terminal.
test -t 0 || exit 1

# When killed, run stty sane.
trap 'stty sane; exit' SIGINT SIGKILL SIGTERM

# When exits, kill this script and it's child processes (the loop).
trap 'kill 0' EXIT

# Do not show ^Key when press Ctrl+Key.
stty -echo -icanon -icrnl time 0 min 0

# While the pears become pears...
while true; do
    xdotool mousemove "$x_pos" "$y_pos" click 1 &
    sleep "$delay"
done & # Note the &: We are running the loop in the background to let read to act.

# Pause until reads a character.
read -n 1

# Exit.
exit 0