Bash 如何解析给定的文件？

我想要一个包含最新utc时间的块（无论是什么）。删除重复的块（非行），仅显示包含最新

utc

时间的块。我希望它是在shell脚本

{
     "cat":  "error",
     "topic":    "glp/0/17q2d9v/rq/dev/iox/dio/do",
     "message":  "ERROR in iox_test handle",
     "utc":  "2018-07-12 12:39:42.670 UTC"
}
{
     "cat":  "error",
     "topic":    "glp/0/17q2d9v/rq/dev/iox/dio/do",
     "message":  "ERROR in iox_test handle",
     "utc":  "2018-07-12 12:39:42.840 UTC"
}
{
     "cat":  "error",
     "topic":    "glp/0/17q2d9v/rq/dev/iox/dio/do",
     "message":  "ERROR in iox_test handle",
     "utc":  "2018-07-12 12:39:42.840 UTC"
}
{
     "cat":  "error",
     "topic":    "glp/0/17q2d9v/rq/dev/iox/dio/do",
     "message":  "ERROR in iox_test handle",
     "utc":  "2018-07-12 12:39:42.840 UTC"
}
{
     "cat":  "error",
     "topic":    "glp/0/17q2d9v/rq/dev/iox/dio/do",
     "message":  "ERROR in iox_test handle",
     "utc":  "2018-07-12 12:39:43.20 UTC"
}
{
     "cat":  "error",
     "topic":    "glp/0/17q2d9v/rq/dev/iox/dio/do",
     "message":  "ERROR in iox_test handle",
     "utc":  "2018-07-12 12:39:43.20 UTC"
}
{
     "cat":  "error",
     "topic":    "glp/0/17q2d9v/rq/dev/iox/dio/do",
     "message":  "ERROR in iox_test handle",
     "utc":  "2018-07-12 12:39:43.20 UTC"
}

例如：我希望给定文件的输出为：

{
     "cat":  "error",
     "topic":    "glp/0/17q2d9v/rq/dev/iox/dio/do",
     "message":  "ERROR in iox_test handle",
     "utc":  "2018-07-12 12:39:43.20 UTC"
}

---

您可以测试以下脚本（假设：数据文件名为file.txt）：

---

假设您的文件是

te1.txt

：

grep 'utc' te1.txt | grep -oP '[[:digit:]].*(?= [[:space:]]*UTC.*)' | sort -k1,2 -ur | head -n1 | xargs -Iregex grep -m1 -B4 -A1 "regex" te1.txt

示例

grep 'utc' te1.txt | grep -oP '[[:digit:]].*(?= [[:space:]]*UTC.*)' | sort -k1,2 -ur | head -n1 | xargs -Iregex grep -m1 -B4 -A1 "regex" te1.txt 
{
    "cat":  "error",
        "topic":    "glp/0/17q2d9v/rq/dev/iox/dio/do",
        "message":  "ERROR in iox_test handle",
        "utc":  "2018-07-12 12:39:43.20 UTC"
}

---

当块是连续的时，您需要最后一个块。
使用

GNU sed 4.2.2

可以使用

sed -z 's/.*}\n{/{/' inputfile

---

你试过什么了吗？shell脚本似乎不适合做这项工作。你甚至可以建议一个python解决方案。。！

sed -z 's/.*}\n{/{/' inputfile