bash脚本-如何处理逗号分隔的列表作为函数的输入参数
我试图弄清楚如何将逗号bash脚本-如何处理逗号分隔的列表作为函数的输入参数,bash,unix,scripting,getopts,Bash,Unix,Scripting,Getopts,我试图弄清楚如何将逗号,分隔列表作为输入传递,并让函数一次处理一个值 我的职能: addToWhitelist () { host='127.0.0.1' db='mytest' _mongo=$(which mongo); echo "${_ip}"; read -a arr <<<${_ip}; for i in ${arr[@]}; do exp="db.account.update({\"account\":'${_a
,
分隔列表作为输入传递,并让函数一次处理一个值
我的职能:
addToWhitelist ()
{
host='127.0.0.1'
db='mytest'
_mongo=$(which mongo);
echo "${_ip}";
read -a arr <<<${_ip};
for i in ${arr[@]};
do
exp="db.account.update({\"account\":'${_account}'},{\$addToSet:{\"ip_list\": {\$each:['${_ip}'] }}})";
${_mongo} ${host}/${db} --eval "$exp"
done
}
addToWhitelist() {
host='127.0.0.1'
db='mytest'
_mongo=$(which mongo)
IFS=, read -a arr <<<"${_ip}"
printf -v ips ',"%s"' "${arr[@]}"
ips="${ips:1}"
exp="db.account.update({'account': '${_account}'}, {\$addToSet:{'ip_list': {\$each:[$ips]}}})";
"${_mongo}" "${host}/${db}" --eval "$exp"
}
但是,调用该函数时遇到的问题是,将值作为单个字符串插入:
"ip_list" : [
"123.456.790.006",
"123.456.790.007,123.456.790.008",
"123.456.790.009"
]
}
期望:
"ip_list" : [
"123.456.790.006",
"123.456.790.007",
"123.456.790.008",
"123.456.790.009"
]
}
试试下面
ip=$(echo${OPTARG}| sed“s/,/,\n/g”)
所以完整的剧本是这样的
#!/usr/local/bin/bash
set -e
set -x
# Usage for getopts
usage () {
echo "Example: $0 -m find -a pizzahut"
echo "Example: $0 -m add -a pizzahut -i 10.10.123.456"
exit 1;
}
while getopts ":m:a:i:" o; do
case "${o}" in
m)
_mode=${OPTARG}
if [[ "${_mode}" != find && "${_mode}" != add ]]; then
usage
fi
;;
a)
_account=${OPTARG}
;;
i)
_ip=$(echo ${OPTARG}|sed "s/,/,\n/g")
set -f
IFS=,
;;
*)
usage
;;
esac
done
shift $((OPTIND-1))
getWhitelist ()
{
host='127.0.0.1'
db='mytest'
_mongo=$(which mongo);
exp="db.account.find({\"account\":'${_account}'},{ip_list: 1}).pretty();";
${_mongo} ${host}/${db} --eval "$exp"
}
# Read a list
addToWhitelist ()
{
host='127.0.0.1'
db='mytest'
_mongo=$(which mongo);
echo "${_ip}";
read -a arr <<<${_ip};
for i in ${arr[@]};
do
exp="db.account.update({\"account\":'${_account}'},{\$addToSet:{\"ip_list\": {\$each:['${_ip}'] }}})";
${_mongo} ${host}/${db} --eval "$exp"
done
}
case "${_mode}" in
'find')
echo "Finding information for the account ${_account}"
getWhitelist
;;
'add')
echo "Adding the following IP: ${_ip}"
addToWhitelist
;;
esac
set +x
#/usr/local/bin/bash
set-e
集合x
#getopts的用法
用法(){
echo“示例:$0-m find-a pizzahut”
echo“示例:$0-m添加-a pizzahut-i 10.10.123.456”
出口1;
}
而getopts:m:a:i:o;做
中的大小写“${o}”
m)
_模式=${OPTARG}
如果[[“${u mode}”!=find&&“${u mode}”!=add]];然后
使用
fi
;;
(a)
_帐户=${OPTARG}
;;
(一)
_ip=$(echo${OPTARG}| sed“s/,/,\n/g”)
set-f
如果=,
;;
*)
使用
;;
以撒
完成
班次$((可选ND-1))
getWhitelist()
{
host='127.0.0.1'
db='mytest'
_mongo=$(哪个mongo);
exp=“db.account.find({\'account\':'${u account}',{ip_list:1}).pretty();”;
${u mongo}${host}/${db}--eval“$exp”
}
#读一份清单
AddToHitelist()
{
host='127.0.0.1'
db='mytest'
_mongo=$(哪个mongo);
回声“${ip}”;
read-a arr因为脚本接收到一个逗号分隔的IP列表,实际上类似于:
_ip="123.456.790.007,123.456.790.008"
在将列表交给Mongo的$each
操作员之前,您需要按,
拆分列表,并用引号将每个IP括起来
首先,将IFS
的重新定义本地化为read
命令,然后利用printf
在提供更多参数时重用相同格式字符串的行为(扩展数组“${arr[@]}”
),通过-v
选项将结果存储到变量中,并从结果中去除前导的,
:
IFS=, read -a arr <<<"${_ip}"
printf -v ips ',"%s"' "${arr[@]}"
ips="${ips:1}"
因此,将其应用到程序中,首先更改i)
的大小写,如:
case "${o}" in
# ...
i) _ip=${OPTARG};;
esac
然后修复addToWhitelist
功能:
addToWhitelist ()
{
host='127.0.0.1'
db='mytest'
_mongo=$(which mongo);
echo "${_ip}";
read -a arr <<<${_ip};
for i in ${arr[@]};
do
exp="db.account.update({\"account\":'${_account}'},{\$addToSet:{\"ip_list\": {\$each:['${_ip}'] }}})";
${_mongo} ${host}/${db} --eval "$exp"
done
}
addToWhitelist() {
host='127.0.0.1'
db='mytest'
_mongo=$(which mongo)
IFS=, read -a arr <<<"${_ip}"
printf -v ips ',"%s"' "${arr[@]}"
ips="${ips:1}"
exp="db.account.update({'account': '${_account}'}, {\$addToSet:{'ip_list': {\$each:[$ips]}}})";
"${_mongo}" "${host}/${db}" --eval "$exp"
}
addToHitelist(){
host='127.0.0.1'
db='mytest'
_mongo=$(哪个mongo)
IFS=,read-a arr谢谢你的回复。我试过了,但是运气不好。我echo
查看输出,它仍然是一样的。123.456.790.007123.456.790.008
你能试试echo-e${OPTARG}sed“s/,\n/g”
?这是我用echo-e${OPTARG sed“s/,\n/g”输出的结果
123.456.790.016,n123.456.790.017
哇!非常感谢您在这方面的帮助。使用printf
是一个很好的处理方法。我感谢您的帮助!