两个和/或一个bash-if语句

我有一个特殊的条件要在bash脚本中测试。 我想到了这样的事情：

if [[ $categorie = "DG" || $categorie = "DI" ]] && [[ $client != "host1" || $client != "host2" ]]; then
    echo "requirements are met"
else
    echo "requirements not met"
fi

换句话说：如果

category

是

DG

或

DI

并且

client

不是

host1

或

host2

，那么就做一些事情

这是正确的吗？

---

对我来说，它似乎只关心

categorie

，如果

categorie

条件得到满足，它就可以打印“满足要求”，而根本不关心客户的条件。

你是对的。由于任何字符串始终不等于两个不同字符串中的至少一个，因此

&&

后面的部分始终为真。

您是正确的。因为任何字符串总是不等于两个不同字符串中的至少一个，所以

&

后面的部分总是正确的。

英语和逻辑学赋予否定或不同的含义-很容易混淆

考虑

$client

的可能值；它们是“host1”、“host2”和“other”。如果值为“host1”，则

|

中的第二项为真；如果是“host2”，则

|

中的第一项为true；如果为“其他”，则

|

中的两个术语均为真；这意味着条件总是正确的

如果客户端不等于主机1，也不等于主机2，则将该

|

替换为

&&

if [[ "$categorie" = "DG" || "$categorie" = "DI" ]] &&
   [[ "$client" != "host1" && "$client" != "host2" ]]; then
    echo "requirements are met"
else
    echo "requirements not met"
fi

或者使用

！（client==host1 | | client==host2）

可转换为：

if [[ "$categorie" = "DG" || "$categorie" = "DI" ]] &&
   [[ ! ( "$client" = "host1" || "$client" = "host2" ) ]]; then
    echo "requirements are met"
else
    echo "requirements not met"
fi

将其放入测试脚本：

for categorie in DG DI XX
do
    for client in host1 host2 other
    do
        if [[ "$categorie" = "DG" || "$categorie" = "DI" ]] &&
           [[ "$client" != "host1" && "$client" != "host2" ]]; then
            echo "(categorie $categorie; client $client): requirements are met"
        else
            echo "(categorie $categorie; client $client): requirements not met"
        fi
        if [[ "$categorie" = "DG" || "$categorie" = "DI" ]] &&
           [[ ! ( "$client" = "host1" || "$client" = "host2" ) ]]; then
            echo "(categorie $categorie; client $client): requirements are met"
        else
            echo "(categorie $categorie; client $client): requirements not met"
        fi
    done
done

输出：

(categorie DG; client host1): requirements not met
(categorie DG; client host1): requirements not met
(categorie DG; client host2): requirements not met
(categorie DG; client host2): requirements not met
(categorie DG; client other): requirements are met
(categorie DG; client other): requirements are met
(categorie DI; client host1): requirements not met
(categorie DI; client host1): requirements not met
(categorie DI; client host2): requirements not met
(categorie DI; client host2): requirements not met
(categorie DI; client other): requirements are met
(categorie DI; client other): requirements are met
(categorie XX; client host1): requirements not met
(categorie XX; client host1): requirements not met
(categorie XX; client host2): requirements not met
(categorie XX; client host2): requirements not met
(categorie XX; client other): requirements not met
(categorie XX; client other): requirements not met

---

线对总是相同的——表达式是等价的。我相信，结果就是你想要的。

英语和逻辑学赋予否定或不同的含义——很容易混淆

考虑

$client

的可能值；它们是“host1”、“host2”和“other”。如果值为“host1”，则

|

中的第二项为真；如果是“host2”，则

|

中的第一项为true；如果为“其他”，则

|

中的两个术语均为真；这意味着条件总是正确的

如果客户端不等于主机1，也不等于主机2，则将该

|

替换为

&&

if [[ "$categorie" = "DG" || "$categorie" = "DI" ]] &&
   [[ "$client" != "host1" && "$client" != "host2" ]]; then
    echo "requirements are met"
else
    echo "requirements not met"
fi

或者使用

！（client==host1 | | client==host2）

可转换为：

if [[ "$categorie" = "DG" || "$categorie" = "DI" ]] &&
   [[ ! ( "$client" = "host1" || "$client" = "host2" ) ]]; then
    echo "requirements are met"
else
    echo "requirements not met"
fi

将其放入测试脚本：

for categorie in DG DI XX
do
    for client in host1 host2 other
    do
        if [[ "$categorie" = "DG" || "$categorie" = "DI" ]] &&
           [[ "$client" != "host1" && "$client" != "host2" ]]; then
            echo "(categorie $categorie; client $client): requirements are met"
        else
            echo "(categorie $categorie; client $client): requirements not met"
        fi
        if [[ "$categorie" = "DG" || "$categorie" = "DI" ]] &&
           [[ ! ( "$client" = "host1" || "$client" = "host2" ) ]]; then
            echo "(categorie $categorie; client $client): requirements are met"
        else
            echo "(categorie $categorie; client $client): requirements not met"
        fi
    done
done

输出：

(categorie DG; client host1): requirements not met
(categorie DG; client host1): requirements not met
(categorie DG; client host2): requirements not met
(categorie DG; client host2): requirements not met
(categorie DG; client other): requirements are met
(categorie DG; client other): requirements are met
(categorie DI; client host1): requirements not met
(categorie DI; client host1): requirements not met
(categorie DI; client host2): requirements not met
(categorie DI; client host2): requirements not met
(categorie DI; client other): requirements are met
(categorie DI; client other): requirements are met
(categorie XX; client host1): requirements not met
(categorie XX; client host1): requirements not met
(categorie XX; client host2): requirements not met
(categorie XX; client host2): requirements not met
(categorie XX; client other): requirements not met
(categorie XX; client other): requirements not met

---

线对总是相同的——表达式是等价的。我相信，结果就是你想要的。

你可以绕过否定或通过与模式进行比较，而不是进行多重比较，这将简化测试

if [[ $categorie == D[GI] ]] && [[ $client != host[12] ]]; then
    echo "requirements are met"
else
    echo "requirements not met"
fi

---

您可以通过对模式进行否定或比较，而不是进行多次比较，从而简化测试

if [[ $categorie == D[GI] ]] && [[ $client != host[12] ]]; then
    echo "requirements are met"
else
    echo "requirements not met"
fi

---

你引用了错误的东西。所有变量都应该被引用，以避免在分词和全局扩展时出现意外，对于所有文本来说，它都是多余的。@Jens我认为双括号可以防止这种情况发生？也许，它们是非标准的（在bash中，它们是对的）。（POSIX标准）单括号不会阻止这一点。在

[[]]

中，引号仅在

=

/

=

的右侧起作用=（带引号：视为字符串，不带引号：视为全局模式）和位于

=~

右侧（带引号：自Bash 3.2以来视为字符串，不带引号：视为正则表达式）。您引用了错误的内容。所有变量都应该被引用，以避免在分词和全局扩展时出现意外，对于所有文本来说，它都是多余的。@Jens我认为双括号可以防止这种情况发生？也许，它们是非标准的（在bash中，它们是对的）。（POSIX标准）单括号不会阻止这一点。在

[[]]

中，引号仅在

=

/

=

的右侧起作用=（带引号：视为字符串，不带引号：视为全局模式）和右侧的

=~

（带引号：自Bash 3.2以来视为字符串，不带引号：视为正则表达式）。非常感谢，就是这样。我在客户端检查中使用

&&

而不是

|

。我没想到否定或会匹配任何东西。非常感谢，就是这个。我在客户端检查中使用

&&

而不是

|

。我没想到否定或将匹配任何东西。