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调用必须有CCS的指针问题

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调用必须有CCS的指针问题,c,texas-instruments,C,Texas Instruments,我是这里的新手，但有一个没有答案的问题。我使用的是来自德克萨斯州的TM4C1294，代码中有无数错误。但首先，我有这个代码。您可以看到，x3从引脚ADC0读取数据，但在通道中给我的错误是obs。忽略前面的星号，代码不完整，因为CCS中身体的其余部分太大。谢谢你的关注 %declaration of pointers to PIN read #define F_SAMPLE 2000 #define x0 *ADC3_read #define x1 *ADC

我是这里的新手，但有一个没有答案的问题。我使用的是来自德克萨斯州的TM4C1294，代码中有无数错误。但首先，我有这个代码。您可以看到，x3从引脚ADC0读取数据，但在通道中给我的错误是obs。忽略前面的星号，代码不完整，因为CCS中身体的其余部分太大。谢谢你的关注

 %declaration of pointers to PIN read
 #define F_SAMPLE   2000    
 #define  x0    *ADC3_read  
 #define  x1    *ADC2_read  
 #define  x2     *ADC1_read  
 #define  x3     *ADC0_read  
 #define  x4     *ADC4_read

 %declaration of variables
 int PI = 3.14159;
 int teste = 0;
 float y_0, ya1, yb1, y_1;
 float y0_aux, ya1_aux, yb1_aux;
 int alfa, i, j;

 %declaration of PIN read
 uint32_t ADC_read[5];              
 uint32_t *ADC0_read=&ADC_read[0];  
 uint32_t *ADC1_read=&ADC_read[1];  
 uint32_t *ADC2_read=&ADC_read[2];   
 uint32_t *ADC3_read=&ADC_read[3];   
 uint32_t *ADC4_read=&ADC_read[4];

%control code
   for( i=0; i <= 12000; i++)
{
    alfa = alfa + (2*PI/200);
   if (alfa >= 2*PI)
      alfa = alfa - 2*PI;
j++;
y0_aux = y0_aux + x3[i]; %error=identifier "x3" is undefined 
ya1_aux = ya1_aux + x3[i]*sin(alfa); 
yb1_aux = yb1_aux + x3[i]*cos(alfa); 
if(j==200){
   y_0 = y0_aux/200;
   ya1 = ya1_aux/200;
   yb1 = yb1_aux/200;

  y_1 = sqrt((ya1 * ya1) + (yb1 * yb1)); 

  y0_aux = 0;
  ya1_aux = 0;
  yb1_aux = 0;
  j = 0;
    }
}
}
警告：这可能不完整，因为我不确定您的最终结果，但我们可以找出编译错误。我不得不稍微随便添加一个主函数，这样我就可以得到一些可编译的东西

这是您的最新程序的更新版本[有错误]：

#include <stdint.h>
#include <math.h>

// declaration of pointers to PIN read
#define F_SAMPLE   2000
#define  x0    *ADC3_read
#define  x1    *ADC2_read
#define  x2     *ADC1_read
#define  x3     *ADC0_read
#define  x4     *ADC4_read

int
main(void)
{

    // declaration of variables
    int PI = 3.14159;
    int teste = 0;
    float y_0,
     ya1,
     yb1,
     y_1;
    float y0_aux,
     ya1_aux,
     yb1_aux;
    int alfa,
     i,
     j;

    // declaration of PIN read
    uint32_t ADC_read[5];
    uint32_t *ADC0_read = &ADC_read[0];
    uint32_t *ADC1_read = &ADC_read[1];
    uint32_t *ADC2_read = &ADC_read[2];
    uint32_t *ADC3_read = &ADC_read[3];
    uint32_t *ADC4_read = &ADC_read[4];

    // control code
    for (i = 0; i <= 12000; i++) {
        alfa = alfa + (2 * PI / 200);
        if (alfa >= 2 * PI)
            alfa = alfa - 2 * PI;
        j++;

        // error = identifier "x3" is undefined
        y0_aux = y0_aux + x3[i];
        ya1_aux = ya1_aux + x3[i] * sin(alfa);
        yb1_aux = yb1_aux + x3[i] * cos(alfa);

        if (j == 200) {
            y_0 = y0_aux / 200;
            ya1 = ya1_aux / 200;
            yb1 = yb1_aux / 200;

            y_1 = sqrt((ya1 * ya1) + (yb1 * yb1));

            y0_aux = 0;
            ya1_aux = 0;
            yb1_aux = 0;
            j = 0;
        }
    }
}
这里有一种方法可以改变事情[这可以干净地编译]：

#include <stdint.h>
#include <math.h>

// declaration of pointers to PIN read
#define F_SAMPLE   2000
#define  x0    ADC3_read
#define  x1    ADC2_read
#define  x2    ADC1_read
#define  x3    ADC0_read
#define  x4    ADC4_read

int
main(void)
{

    // declaration of variables
    int PI = 3.14159;
    int teste = 0;
    float y_0,
     ya1,
     yb1,
     y_1;
    float y0_aux,
     ya1_aux,
     yb1_aux;
    int alfa,
     i,
     j;

    // declaration of PIN read
    uint32_t ADC_read[5];
    uint32_t *ADC0_read = &ADC_read[0];
    uint32_t *ADC1_read = &ADC_read[1];
    uint32_t *ADC2_read = &ADC_read[2];
    uint32_t *ADC3_read = &ADC_read[3];
    uint32_t *ADC4_read = &ADC_read[4];

    // control code
    for (i = 0; i <= 12000; i++) {
        alfa = alfa + (2 * PI / 200);
        if (alfa >= 2 * PI)
            alfa = alfa - 2 * PI;
        j++;

        // error = identifier "x3" is undefined
        y0_aux = y0_aux + x3[i];
        ya1_aux = ya1_aux + x3[i] * sin(alfa);
        yb1_aux = yb1_aux + x3[i] * cos(alfa);

        if (j == 200) {
            y_0 = y0_aux / 200;
            ya1 = ya1_aux / 200;
            yb1 = yb1_aux / 200;

            y_1 = sqrt((ya1 * ya1) + (yb1 * yb1));

            y0_aux = 0;
            ya1_aux = 0;
            yb1_aux = 0;
            j = 0;
        }
    }
}

#include <stdint.h>
#include <math.h>

// declaration of pointers to PIN read
#define F_SAMPLE   2000
#define  x0(o)    ADC3_read[o]
#define  x1(o)    ADC2_read[o]
#define  x2(o)    ADC1_read[o]
#define  x3(o)    ADC0_read[o]
#define  x4(o)    ADC4_read[o]

int
main(void)
{

    // declaration of variables
    int PI = 3.14159;
    int teste = 0;
    float y_0,
     ya1,
     yb1,
     y_1;
    float y0_aux,
     ya1_aux,
     yb1_aux;
    int alfa,
     i,
     j;

    // declaration of PIN read
    uint32_t ADC_read[5];
    uint32_t *ADC0_read = &ADC_read[0];
    uint32_t *ADC1_read = &ADC_read[1];
    uint32_t *ADC2_read = &ADC_read[2];
    uint32_t *ADC3_read = &ADC_read[3];
    uint32_t *ADC4_read = &ADC_read[4];

    // control code
    for (i = 0; i <= 12000; i++) {
        alfa = alfa + (2 * PI / 200);
        if (alfa >= 2 * PI)
            alfa = alfa - 2 * PI;
        j++;

        // error = identifier "x3" is undefined
        y0_aux = y0_aux + x3(i);
        ya1_aux = ya1_aux + x3(i) * sin(alfa);
        yb1_aux = yb1_aux + x3(i) * cos(alfa);

        if (j == 200) {
            y_0 = y0_aux / 200;
            ya1 = ya1_aux / 200;
            yb1 = yb1_aux / 200;

            y_1 = sqrt((ya1 * ya1) + (yb1 * yb1));

            y0_aux = 0;
            ya1_aux = 0;
            yb1_aux = 0;
            j = 0;
        }
    }
}
老实说，我看不出单个指针ADC3\u read等如何适应[well]

重新定义如下：定义x3offset\u ADC0\u read[offset\u]，我认为这会起作用。同样，对于其他宏。@CraigEstey现在在表达式y0_aux=y0_aux+*x3i中给出了以下错误：；*的操作数必须是指针。我已更改为指针，但什么也没有发生，我必须做什么？按照[原始]说明：-。也就是说，我说的是更改定义，而不是其他任何内容。你的原始方程是y0_aux=y0_aux+x3i。有了这一点，再加上我建议的“定义变化”，它就会起作用。但是，您也[错误地]通过执行y0_aux=y0_aux+*x3i添加了一个*。请理解，要取消对带有偏移量的指针的引用，可以执行以下操作：*ptr+off或[这通常更可取]：ptr[off]。您的第二次尝试相当于*ptr[off]，这是不同的。所以，只需删除额外的*我已经按照您最初的指示：但没有工作：这就是为什么我做了更改。然而，即使采纳了您所说的，错误仍然存在。此时，我将编辑您的问题并发布[更多]您的完整代码，包括ADC0_read的定义等。我的假设是它类似于定义ADC0_read 0x8010。此外，y0_aux等的定义也会发布准确的错误消息 
#include <stdint.h>
#include <math.h>

// declaration of pointers to PIN read
#define F_SAMPLE   2000
#define  x0(o)    ADC3_read[o]
#define  x1(o)    ADC2_read[o]
#define  x2(o)    ADC1_read[o]
#define  x3(o)    ADC0_read[o]
#define  x4(o)    ADC4_read[o]

int
main(void)
{

    // declaration of variables
    int PI = 3.14159;
    int teste = 0;
    float y_0,
     ya1,
     yb1,
     y_1;
    float y0_aux,
     ya1_aux,
     yb1_aux;
    int alfa,
     i,
     j;

    // declaration of PIN read
    uint32_t ADC_read[5];
    uint32_t *ADC0_read = &ADC_read[0];
    uint32_t *ADC1_read = &ADC_read[1];
    uint32_t *ADC2_read = &ADC_read[2];
    uint32_t *ADC3_read = &ADC_read[3];
    uint32_t *ADC4_read = &ADC_read[4];

    // control code
    for (i = 0; i <= 12000; i++) {
        alfa = alfa + (2 * PI / 200);
        if (alfa >= 2 * PI)
            alfa = alfa - 2 * PI;
        j++;

        // error = identifier "x3" is undefined
        y0_aux = y0_aux + x3(i);
        ya1_aux = ya1_aux + x3(i) * sin(alfa);
        yb1_aux = yb1_aux + x3(i) * cos(alfa);

        if (j == 200) {
            y_0 = y0_aux / 200;
            ya1 = ya1_aux / 200;
            yb1 = yb1_aux / 200;

            y_1 = sqrt((ya1 * ya1) + (yb1 * yb1));

            y0_aux = 0;
            ya1_aux = 0;
            yb1_aux = 0;
            j = 0;
        }
    }
}

uint32_t ADC_read[12000];

#define x3(o)   ADC_read[(o) + 0]
#define x2(o)   ADC_read[(o) + 1]
...