C 我能'；无法正确执行if语句

我似乎无法在程序的存款和取款部分正确执行if语句。当数字为负数时，它将正确执行，但当数字为正数时，它将显示错误消息，然后结束循环并移动到取款

#include <stdio.h>
int main (void)
{
    int deposits = 0, totaldeposits = 0, deposited = 0, totalwithdrawals = 0, withdrawals, d = 0, w = 0;
    float balance = 0, b;

        printf ("Welcome to the computer banking system\n\n");

    for ( b = 0; b <= balance; ++b )
    {
        printf ("Enter your current balance in dollars and cents:");
            scanf ("%f", &b);
            balance = balance + b;

        if ( balance <= -1 )
        {
            printf ("***Beginning balance must be at least zero, please re-enter.\n\n");
                balance = balance - b, --b;

        }/*end of if statement*/
    }/*end of for loop*/

    for ( d = 0; d <= deposits; ++d )
    {       
        printf ("\nEnter the number of deposits (0-5):");
            scanf ("%i", &d);
        deposits = deposits + d;

        if ( deposits > 5 || deposits < 0 )
        {
            printf ("*** Invalid number of deposits, please re-enter.");
                deposits = deposits - d;
        }/*end of if statement for deposits*/       
    }/*end of for loop for deposits*/
    for ( w <= 0; w <= withdrawals; ++w)
    {
        printf ("\n\nEnter the number of withdrawals (0-5):");
            scanf ("%i", &w);
            withdrawals = withdrawals + w, ++w;

        if ( withdrawals > 5 || withdrawals < 0 )
        {
        printf ("***Invalid number of withdrawals, please re-enter.");
        withdrawals = withdrawals - w, --w;
        }/*end of withdrawals if*/
    }/*end of withdrawals for loop*/





getchar;        
return 0;

} /*End main*/

#包括
内部主（空）
{
整数存款=0，总存款=0，存款=0，总取款=0，取款，d=0，w=0；
浮动平衡=0，b；
printf（“欢迎使用计算机银行系统\n\n”）；
对于（b=0；b您在for循环和获取输入中使用了相同的变量d。这导致了问题。请使用以下代码：-

int dep;
for ( d = 0; d <= deposits; ++d )
{       
    printf ("\nEnter the number of deposits (0-5):");
        scanf ("%i", &dep);
    deposits = deposits + dep;

    if ( deposits > 5 || deposits < 0 )
    {
        printf ("*** Invalid number of deposits, please re-enter.");
            deposits = deposits - dep;
    }/*end of if statement for deposits*/  
    else break;     
}/*end o

intdep；
对于（d=0；d 5 | |存款<0）
{
printf（“***存款数量无效，请重新输入。”）；
存款=存款-dep；
}/*存款的if结单*/
否则就断了；
}/*结束o
您的程序逻辑似乎有错误。我会重写

for ( d = 0; d <= deposits; ++d )
{       
    printf ("\nEnter the number of deposits (0-5):");
        scanf ("%i", &d);
    deposits = deposits + d;

    if ( deposits > 5 || deposits < 0 )
    {
        printf ("*** Invalid number of deposits, please re-enter.");
            deposits = deposits - d;
    }/*end of if statement for deposits*/       
}/*end of for loop for deposits*/

（d=0；d 5 | |存款<0）的

{
printf（“***存款数量无效，请重新输入。”）；
存款=存款-d；
}/*存款的if结单*/
}/*存款循环结束*/

作为

do{
printf（“\n输入存款数量（0-5）：”；
scanf（“%i”和存款）；
如果（存款<0 | |存款>5）{
printf（“***存款数量无效，请重新输入。”）；
}否则{
打破
}
}而(1),；

其他循环也可以这样做

我们的想法是至少要求输入一次，然后检查输入的值是否对您的案例有效，如果无效，请再次要求输入。
如果是
语句，会是哪个
？非常感谢您的帮助！我真的非常感谢！非常感谢您的帮助！我真的非常感谢。我不理解do循环，但它们是正确的在这之后更清楚了。再次感谢！
do {
    printf ("\nEnter the number of deposits (0-5):");
    scanf ("%i", &deposits);

    if (deposits < 0 || deposits > 5) {
        printf ("*** Invalid number of deposits, please re-enter.");
    } else {
        break;
    }
} while (1);