C 为什么这只是打印最后一个字?

C 为什么这只是打印最后一个字?,c,pointers,structure,C,Pointers,Structure,我真的很难调试这个。当我试图打印出结构时,我只知道最后一个字。我是在记忆中写东西还是什么?有人能帮我吗 typedef struct hash_table_ { void **order; int *number_next_calls; int *number_buckets; int *buckets_size; int *worst; int *total; float *average; int (*hash_func)(char *); data_el

我真的很难调试这个。当我试图打印出结构时,我只知道最后一个字。我是在记忆中写东西还是什么?有人能帮我吗

typedef struct hash_table_ {
  void **order;
  int *number_next_calls;
  int *number_buckets;
  int *buckets_size;
  int *worst;
  int *total;
  float *average;
  int (*hash_func)(char *);
  data_el **buckets_array;
} hash_table, *Phash_table;

typedef struct data_{
  char *key;
  void *data;
  struct data_ *next;
}data_el;

main(){

while ((c = getchar()) != EOF) {
    if ((c == ' ') || (c == ',') || (c == '.') || (c == '!') || (c == '"') ||
        (c == ':') || (c == '\n')) {

      /* End of a word */
      if (char_index) {
        /* Word is not empty */
        word[char_index] = '\0';
        lower_case_word(word);
        if(!find_hash(dictionary,word) ){
          insert_hash(dictionary,word,frequency[hash_function(word)]);
        }
        printf("%s\n", dictionary -> buckets_array[hash_function(word)] -> key);
        printf("%d \n",hash_function(word));
        frequency[hash_function(word)]++;
        char_index = 0;
        num_words++;
      }
    }else{
      word[char_index++] = c;
    }
  }

/*This is when it prints*/
  printf("%s\n", dictionary -> buckets_array[337] -> key);
  printf("%s\n", dictionary -> buckets_array[532] -> key);
  printf("%s\n", dictionary -> buckets_array[93] -> key);

 }

 int hash_function(char *word){

  int sum,i;
  i = 0;
  sum = 0;
  while(word[i] != '\0'){
    sum = sum + word[i];
    i++;
  }
  return sum%1000;
}

void insert_hash(Phash_table table, char *key, void *data){
  int index;
  data_el *p, *cur;

  index = table -> hash_func(key);

  /*Head insertion*/
  if(table -> buckets_array[index] == NULL){
    table -> buckets_array[index] = (data_el *)malloc(sizeof(data_el));
    table -> buckets_array[index] -> data = data;
    table -> buckets_array[index] -> next =  NULL;
    table -> buckets_array[index] -> key = key;
  }else{
    printf("%s",table -> buckets_array[index] -> key);
    cur = table -> buckets_array[index];
    p = (data_el *)malloc(sizeof(data_el));
    p -> key = key;
    p -> data = data;
    p -> next = cur;
    cur = p;
    /*
    table -> buckets_array[index] = cur;
    */
  }
}

insert_hash
中,您有

table -> buckets_array[index] -> key = key;
响应

也就是说,让bucket入口指向从
main
传递的相同内存。代码不完整,所以我不能确定,但我敢打赌它
main
可以重用
word
数组,并且在每次插入后不会分配新数组。因此,
table->bucket\u array[index]->key
所指向的字符串的内容被覆盖


您必须将字符串复制到新的内存块中,并让bucket条目指向该块。

这是大量代码,请将问题隔离到程序的某个特定部分,您应该使用调试器或打印语句,并且还应该提供一个示例输入和输出(预期和实际)为了帮助我们更好地理解这个问题,当我使用while函数时,我使用printf来查看它正在存储的数据,它正在打印刚刚扫描进来的数据,这是正确的。使用while循环完成后,我尝试打印它
printf(“%s\n”,dictionary->bucket\u array[337]->key);printf(“%s\n”,dictionary->bucket\u array[532]->key);printf(“%s\n”,dictionary->bucket\u array[93]->key)但它只是给了我最后扫描的内容。风格说明:运算符优先级有时对您有利:
*(table->total)=*(table->total)+1可以写为
*表->总计=*表->总计+1,可进一步缩减为
*表->合计+=1这个
->
绑得很紧!。类似于
(表->存储桶大小[index])=(表->存储桶大小[index])+1-->
表格->存储桶大小[索引]+=1
int hashfunction()
有时会返回负值,通常会将其用作数组索引。危险,威尔·罗宾逊!
p -> key = key;