C-阵列未填充时fgets挂起

我使用

fgets（）

从

stdin

获取输入，似乎在缓冲区溢出方面遇到了一些问题。我已经添加了一个while循环，它意味着吃掉所有字符，但是我的代码运行了多次，应该只运行一次

void play_game(void) {
    int ch; /* Waste */
    /* Max input from fgets */
    char c[8];

    enum cell_contents board[BOARD_HEIGHT][BOARD_WIDTH];

    init_board(board);

    while(!is_game_over(board)) {
        display_board(board);

        printf("Please enter a move [enter Q or ctrl-D to quit]: ");

        if(fgets(c, sizeof(c), stdin)) {
            printf("Entered: %s\n", c);
            struct move calculated_move = calculate_move(c);

            if(is_valid_move(calculated_move, board))
                player_move(calculated_move, board);
            else
                printf("That is an invalid move!\n");
        }

        /* eat excess data */
        if (strlen(c) == sizeof(c)-1)
            while((ch = fgetc(stdin)) != '\n' && ch != EOF);

        /* eat overfilled data */
        //read_rest_of_line();

    }

    printf("Game over!\n");
    game_over(board);
}

以下是我的结果：

Please enter a move [enter Q or ctrl-D to quit]: E4, C4 gfgfd oigjdfogkf dohdfkho dk
Entered: E4, C4 
            +---+---+---+        
1           | o | o | o |        
            +---+---+---+        
2           | o | o | o |        
    +---+---+---+---+---+---+---+
3   | o | o | o | o | o | o | o |
    +---+---+---+---+---+---+---+
4   | o | . | o | . | . | o | o |
    +---+---+---+---+---+---+---+
5   | o | o | o | o | o | o | o |
    +---+---+---+---+---++---+---+
6           | o | o | o |        
            +---+---+---+        
7           | o | o | o |        
            +---+---+---+        
      A   B   C   D   E   F   G   
Please enter a move [enter Q or ctrl-D to quit]: Entered: gfgfd o
That is an invalid move!
            +---+---+---+        
1           | o | o | o |        
            +---+---+---+        
2           | o | o | o |        
    +---+---+---+---+---+---+---+
3   | o | o | o | o | o | o | o |
    +---+---+---+---+---+---+---+
4   | o | . | o | . | . | o | o |
    +---+---+---+---+---+---+---+
5   | o | o | o | o | o | o | o |
    +---+---+---+---+---++---+---+
6           | o | o | o |        
            +---+---+---+        
7           | o | o | o |        
            +---+---+---+        
      A   B   C   D   E   F   G   
Please enter a move [enter Q or ctrl-D to quit]: Entered: igjdfog
That is an invalid move!
            +---+---+---+        
1           | o | o | o |        
            +---+---+---+        
2           | o | o | o |        
    +---+---+---+---+---+---+---+
3   | o | o | o | o | o | o | o |
    +---+---+---+---+---+---+---+
4   | o | . | o | . | . | o | o |
    +---+---+---+---+---+---+---+
5   | o | o | o | o | o | o | o |
    +---+---+---+---+---++---+---+
6           | o | o | o |        
            +---+---+---+        
7           | o | o | o |        
            +---+---+---+        
      A   B   C   D   E   F   G   
Please enter a move [enter Q or ctrl-D to quit]: 

---

通过检查数组中的最后一个字符是否为新行修复了此问题

/* eat excess data */
if (strlen(c) == sizeof(c)-1 || c[sizeof(c)-1] != '\n')
    read_rest_of_line();

void read_rest_of_line(void){
    int ch;
    /* remove all characters from the buffer */
    while (ch = getc(stdin), ch != '\n' && ch != EOF);

    /* clear the error status of the input pointer */
    clearerr(stdin);
}

---

如果您给缓冲区指定了正确的大小，则不会写入超过缓冲区结尾的内容。但是，如果换行符符合缓冲区的要求，它可以添加换行符。至于您的问题，请尝试在调试器中逐行检查代码，同时注意变量及其内容。它可能会帮助您找出问题所在。此外，请小心使用该循环以耗尽剩余的字符。如果用户输入了6个字符和换行符怎么办？然后

strlen（c）==sizeof（c）-1

也将为真，您将开始从下一行读取字符（或者更确切地说，当

fgetc

等待输入时，游戏似乎会锁定）。更好的检查是缓冲区中的最后一个字符是否为换行符。如果从

stdin

中删除使用剩余字符的循环，会发生什么情况？我将如何处理此Joachim？