迭代不返回所有值CakePhp

我正在尝试获得一个帐户正在跟踪的用户的所有帖子。我有一个查询，检查当前用户在跟踪谁，该查询工作正常（返回所有值|下面的代码）

问题是当我尝试获取帖子时，我只获得一个用户的帖子。有什么问题的建议吗

$all_posts_following = NULL;

        foreach($all_following as $follower)
        {
            $postsTable=TableRegistry::get('Posts');
            $all_posts_following = $postsTable->find('all')->where(['Posts.user_fk' => $follower[('followed_fk')]])->toArray();
        }

        $this->set("all_posts_following",$all_posts_following); 

---

您正在覆盖之前分配给

所有帖子的值

如果要附加到数组，请使用
array\u merge

    $all_posts_following = [];
    $postsTable = TableRegistry::get('Posts');
    foreach($all_following as $follower)
    {
        $posts = $postsTable->find('all')->where(['Posts.user_fk' => $follower[('followed_fk')]])->toArray();
        $all_posts_following = array_merge($all_posts_following, $posts);
    }

    $this->set("all_posts_following",$all_posts_following); 

或者，您可以使用
IN
操作符查询所有匹配项

    $postsTable = TableRegistry::get('Posts');
    $all_posts_following = $postsTable->find('all')
       ->where(['
           Posts.user_fk IN' => $all_following
    ])->toArray();

请记住，当您调用
toArray（）
时，MySQL驱动程序会在将所有记录发送到视图之前将其读取到内存中。如果您知道只需要迭代（循环）记录，那么将查询传递给视图，并在
foreach
中使用它

    $postsTable = TableRegistry::get('Posts');
    $all_posts_following = $postsTable->find('all')
       ->where(['
           Posts.user_fk IN' => $all_following
    ])->toArray();