Class 在Fortran中从外部类传递子例程名称
在中,我们学习了如何在Fortran类中传递子例程名称作为参数。但是我们如何从外部类传递子例程名称呢 随后的代码使用GNU Fortran(GCC)5.1.0为两次不同的尝试生成编译错误: 例程Class 在Fortran中从外部类传递子例程名称,class,oop,fortran,gfortran,subroutine,Class,Oop,Fortran,Gfortran,Subroutine,在中,我们学习了如何在Fortran类中传递子例程名称作为参数。但是我们如何从外部类传递子例程名称呢 随后的代码使用GNU Fortran(GCC)5.1.0为两次不同的尝试生成编译错误: 例程选择器的目标是采用不同的计算路径:一个是将数字平方,另一个是将其加倍。第一个编译错误建议添加参数列表。对此天真的补救措施会产生第二个错误 随后是一个MWE。排列编程产生了许多变体;希望这个版本可以很容易地修复 module myModule implicit none type
选择器的目标是采用不同的计算路径:一个是将数字平方,另一个是将其加倍。第一个编译错误建议添加参数列表。对此天真的补救措施会产生第二个错误
随后是一个MWE。排列编程产生了许多变体;希望这个版本可以很容易地修复
module myModule
implicit none
type :: intermediates
real :: z
contains
private
procedure, nopass, public :: square => square_sub
procedure, nopass, public :: double => double_sub
end type intermediates
private :: square_sub
private :: double_sub
contains
subroutine square_sub ( x, y )
real, intent ( in ) :: x
real, intent ( out ) :: y
y = x ** 2
end subroutine square_sub
subroutine double_sub ( x, y )
real, intent ( in ) :: x
real, intent ( out ) :: y
y = x * 2
end subroutine double_sub
end module myModule
program casey
use myModule
implicit none
real :: x = 10.0, y
type ( intermediates ) :: ints
call selector ( ints % square, x , y )
call selector ( ints % double ( x, y ), x , y )
contains
subroutine selector ( sub, x, y )
interface mySub
subroutine sub ( x, y )
real, intent ( in ) :: x
real, intent ( out ) :: y
end subroutine sub
end interface mySub
real, intent ( in ) :: x
real, intent ( out ) :: y
call sub ( x, y )
print *, 'x = ', x, ', y = ', y
end subroutine selector
end program casey
解决方案是将选择器过程放置在类中。在上面的示例中,子例程选择器
位于程序
内。下面的子程序本地\u选择器
是类型mySubs
中的过程
module mySubs
implicit none
type :: myClass
contains
procedure, nopass, public :: square
procedure, nopass, public :: double
procedure, nopass, public :: local_selector
end type myClass
contains
subroutine square ( x, y )
real, intent ( in ) :: x
real, intent ( out ) :: y
y = x ** 2
print *, 'x = ', x, '; x ** 2 = ', y
end subroutine square
subroutine double ( x, y )
real, intent ( in ) :: x
real, intent ( out ) :: y
y = x * 2
print *, 'x = ', x, '; 2 x = ', y
end subroutine double
subroutine local_selector ( sub, x, y )
interface mySub
subroutine sub ( x, y )
real, intent ( in ) :: x
real, intent ( out ) :: y
end subroutine sub
end interface mySub
real, intent ( in ) :: x
real, intent ( out ) :: y
call sub ( x, y )
end subroutine local_selector
end module mySubs
program fixed
use mySubs
implicit none
real :: x = 10.0, y
type ( myClass ) :: thisClass
call thisClass % local_selector ( square, x , y )
call thisClass % local_selector ( double, x , y )
end program fixed
我认为应该有另一个问题向你指出。相反,在短期内,ints%square
不是一个过程,而是一个绑定名称。这可能足以让您继续搜索。请阅读您引用的操作“内部”和“外部”类(在Fortran中称为派生类型)-Fortran中的派生类型内部没有可执行操作。类型具有绑定和过程指针组件,这些绑定和组件引用的过程总是在派生类型定义的范围之外。
module mySubs
implicit none
type :: myClass
contains
procedure, nopass, public :: square
procedure, nopass, public :: double
procedure, nopass, public :: local_selector
end type myClass
contains
subroutine square ( x, y )
real, intent ( in ) :: x
real, intent ( out ) :: y
y = x ** 2
print *, 'x = ', x, '; x ** 2 = ', y
end subroutine square
subroutine double ( x, y )
real, intent ( in ) :: x
real, intent ( out ) :: y
y = x * 2
print *, 'x = ', x, '; 2 x = ', y
end subroutine double
subroutine local_selector ( sub, x, y )
interface mySub
subroutine sub ( x, y )
real, intent ( in ) :: x
real, intent ( out ) :: y
end subroutine sub
end interface mySub
real, intent ( in ) :: x
real, intent ( out ) :: y
call sub ( x, y )
end subroutine local_selector
end module mySubs
program fixed
use mySubs
implicit none
real :: x = 10.0, y
type ( myClass ) :: thisClass
call thisClass % local_selector ( square, x , y )
call thisClass % local_selector ( double, x , y )
end program fixed