Clojure 生成长度为N的相同项的向量

我想在给定项目和计数的情况下生成相同项目的向量。这似乎比使用循环更容易实现。有没有让下面的功能更紧凑/精简的想法

;take an object and a nubmer n and return a vector of those objects that is n-long
(defn return_multiple_items [item number-of-items]
    (loop [x 0
           items [] ]
      (if (= x number-of-items)
           items
           (recur (+ x 1)
                  (conj items item)))))

>(return_multiple_items "A" 5 )
>["A" "A" "A" "A" "A"]
>(return_multiple_items {:years 3} 3)
>[{:years 3} {:years 3} {:years 3}]

---

有一个专门为这种情况设计的内置功能：

> (repeat 5 "A")
("A" "A" "A" "A" "A")

如您所见，它产生了一系列相同的元素。如果您需要向量，可以使用以下方法转换：

---

repeat

功能在这里派上了用场：

user> (defn return-multiple-items [item how-many] 
         (vec (repeat how-many item)))
#'user/return-multiple-items

user> (return-multiple-items "A" 5)
["A" "A" "A" "A" "A"]

---

这正是我想要的。我在clojure文档上翻了一会儿，找不到我要找的东西。谢谢

user> (defn return-multiple-items [item how-many] 
         (vec (repeat how-many item)))
#'user/return-multiple-items

user> (return-multiple-items "A" 5)
["A" "A" "A" "A" "A"]

user> (into [] (repeat 5 "A"))
["A" "A" "A" "A" "A"]

user> (into [] (repeat 3 {:years 3}))
[{:years 3} {:years 3} {:years 3}]