将clojure代码放入循环中 (def抛出10) (定义r平方[xy] (+(*(-0.5倍)(-0.5倍)) (*(-0.5 y)(-0.5 y))) (循环[点击0] (让[x(兰特) y(兰特)] ;仍在出租房内 (如果(
我让代码工作并运行,直到if条件为真。如何重写它,使其以X为参数并运行X次将clojure代码放入循环中 (def抛出10) (定义r平方[xy] (+(*(-0.5倍)(-0.5倍)) (*(-0.5 y)(-0.5 y))) (循环[点击0] (让[x(兰特) y(兰特)] ;仍在出租房内 (如果(,clojure,Clojure,我让代码工作并运行,直到if条件为真。如何重写它,使其以X为参数并运行X次 我基本上想调用(r平方100)并得到我得到的点击次数作为返回值。如果正确理解这个问题,我想这就是你们想要的 (def throws 10) (defn r-squared [x y] (+ (* (- 0.5 x) (- 0.5 x)) (* (- 0.5 y) (- 0.5 y)))) (loop [hits 0] (let [x (rand) y (rand)] ; st
我基本上想调用(r平方100)并得到我得到的点击次数作为返回值。如果正确理解这个问题,我想这就是你们想要的
(def throws 10)
(defn r-squared [x y]
(+ (* (- 0.5 x) (- 0.5 x))
(* (- 0.5 y) (- 0.5 y))))
(loop [hits 0]
(let [x (rand)
y (rand)]
; still inside the let
(if (< (r-squared x y) 0.25) ;is it a hit or not? if not, try again
(recur (inc hits))
(* 4 (/ hits throws)))))
(defn测试[n]
(循环[点击0 n]
(让[x(兰特)
y(兰特)]
(如果(没有评估它,所以parn可能有点错误
(defn test [n]
(loop [hits 0 n n]
(let [x (rand)
y (rand)]
(if (< n 0)
hits ;// you can put (* 4 (/ hits throws)) here
(if (< (r-squared x y) 0.25)
(recur (inc hits) (dec n))
(recur hits (dec n)))))))
(def抛出10)
(定义r平方[xy]
(+(*(-0.5倍)(-0.5倍))
(*(-0.5 y)(-0.5 y)))
(defn测试-r平方[n]
(循环[点击次数(整数0)n(整数n)]
(让[x(兰特)
y(兰特)]
;仍在出租房内
(如果((定义r平方[xy]
(+(*(-0.5倍)(-0.5倍))
(*(-0.5 y)(-0.5 y)))
(defn hit[]
(让[x(兰特)y(兰特)]
(<(r平方x y)0.25)))
(频率(针对[i(范围1000)](命中));{真787,假213}
我如何及时包装这个以获得执行时间?及时包装您的测试调用<代码>(时间(测试100))
代码从不更改n的值。对于任何大于0的n,它都相当于海报的初始代码。
(def throws 10)
(defn r-squared [x y]
(+ (* (- 0.5 x) (- 0.5 x))
(* (- 0.5 y) (- 0.5 y))))
(defn test-r-squared [n]
(loop [hits (int 0) n (int n)]
(let [x (rand)
y (rand)]
; still inside the let
(if (< n 0)
(* 4 (/ hits throws))
(if (< (r-squared x y) 0.25) ;is it a hit or not? if not, try again
(recur (inc hits) (dec n))
(recur hits (dec n)))))))
(defn r-squared [x y]
(+ (* (- 0.5 x) (- 0.5 x))
(* (- 0.5 y) (- 0.5 y))))
(defn hit[]
(let [x (rand) y (rand)]
(< (r-squared x y) 0.25)))
(frequencies (for [i (range 1000)] (hit))) ; {true 787, false 213}