Cobol 是否仅为工作存储部分中的字段添加工作。?
像这样的程序似乎不起作用Cobol 是否仅为工作存储部分中的字段添加工作。?,cobol,gnucobol,Cobol,Gnucobol,像这样的程序似乎不起作用 PROGRAM-ID. Test. ENVIRONMENT DIVISION. INPUT-OUTPUT SECTION. FILE-CONTROL. SELECT CountFile ASSIGN TO "count.dat" ORGANIZATION IS LINE SEQUENTIAL. DATA DIVISION. FILE SECTION. FD CountFile. 0
PROGRAM-ID. Test.
ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
SELECT CountFile ASSIGN TO "count.dat"
ORGANIZATION IS LINE SEQUENTIAL.
DATA DIVISION.
FILE SECTION.
FD CountFile.
01 CountDetails.
02 FCountA PIC 99 VALUE 0.
02 FCountB PIC 99 VALUE 0.
WORKING-STORAGE SECTION.
PROCEDURE DIVISION.
Begin.
OPEN OUTPUT CountFile
ADD 1 TO FCountA
ADD 1 TO FCountB
WRITE CountDetails
CLOSE CountFile
STOP RUN.
这会将9999写入count.dat文件。添加适用于工作存储部分中的字段,但不适用于文件部分中的字段
那是真的吗?问:那是真的吗?A:不,不是
ADD
适用于任何数字字段,无论其存储在何处
请注意,文件部分
中的数据仅保证在成功打开后可用(正如您提到的GnuCOBOL:此部分始终提供存储)。它没有任何保证值,因此您可能需要初始化数据
示例COBOL示例显示了这两者,可以是:
注意:它是固定格式的参考格式,不一定是可移植的,缺少的OPEN
可能意味着它会中止-这不是任何合理的好样式-但是可以演示这个问题。谢谢。初始化修复了它。
IDENTIFICATION DIVISION.
PROGRAM-ID. HELLO-WORLD.
ENVIRONMENT DIVISION.
input-output section.
file-control.
select test-file
assign to 'test-file'
organization is line sequential.
data division.
file section.
fd test-file.
01 num-var pic 9 value 0.
working-storage section.
01 num2-var pic 9 value 0.
PROCEDURE DIVISION.
ADD 1 TO num-var num2-var
DISPLAY 'Hello, num ' num2-var ' and file ' num-var.
INITIALIZE num-var num2-var
ADD 1 TO num-var num2-var
DISPLAY 'Hello, num ' num2-var ' and file ' num-var.
ADD num2-var to num-var
ADD num2-var to num-var
DISPLAY 'Hello, num ' num2-var ' and file ' num-var.
ADD num-var to num-var
DISPLAY 'Hello, num ' num2-var ' and file ' num-var.
STOP RUN.