Couchbase-从对象数组中选择字段子集

我正在使用

旅行样本

数据集，并正在运行以下查询：

SELECT id, schedule FROM `travel-sample`WHERE type = "route" LIMIT 1;

它将返回以下结果：

[
  {
    "id": 10000,
    "schedule": [
      {
        "day": 0,
        "flight": "AF198",
        "utc": "10:13:00"
      },
      {
        "day": 0,
        "flight": "AF547",
        "utc": "19:14:00"
      },
      ...
    ]
  }
]

但是，我不想返回

schedule.$.day

字段；i、 e.我希望我的结果是：

[
  {
    "id": 10000,
    "schedule": [
      {
        "flight": "AF198",
        "utc": "10:13:00"
      },
      {
        "flight": "AF547",
        "utc": "19:14:00"
      },
      ...
    ]
  }
]

[
  {
    "id": 10000,
    "schedule": [
      {
        "flight": "AF198",
        "utc": "10:13:00"
      },
      {
        "flight": "AF547",
        "utc": "19:14:00"
      },
      ...
    ]
  }
]

如何从对象数组中仅选择对象字段的子集

---

我尝试了

UNNEST

，但我不想为每个

schedule

元素创建单独的记录-我希望

schedule

元素保持嵌套在文档中

我还尝试过使用

OBJECT\u REMOVE

SELECT id, ARRAY OBJECT_REMOVE(x, 'day') FOR x in schedule END AS schedule FROM `travel-sample` WHERE type = "route" LIMIT 1;

---

但我想将字段列入白名单而不是黑名单。

您上次的尝试已接近成功。您不必使用

对象\u REMOVE

，只需构造想要返回的对象即可

SELECT id, ARRAY {"flight": x.flight, "utc": x.utc} FOR x in schedule END AS schedule FROM `travel-sample` WHERE type = "route" LIMIT 1;

您将获得以下结果：

[
  {
    "id": 10000,
    "schedule": [
      {
        "day": 0,
        "flight": "AF198",
        "utc": "10:13:00"
      },
      {
        "day": 0,
        "flight": "AF547",
        "utc": "19:14:00"
      },
      ...
    ]
  }
]

---

你的最后一次尝试很接近。您不必使用

对象\u REMOVE

，只需构造想要返回的对象即可

SELECT id, ARRAY {"flight": x.flight, "utc": x.utc} FOR x in schedule END AS schedule FROM `travel-sample` WHERE type = "route" LIMIT 1;

您将获得以下结果：

[
  {
    "id": 10000,
    "schedule": [
      {
        "day": 0,
        "flight": "AF198",
        "utc": "10:13:00"
      },
      {
        "day": 0,
        "flight": "AF547",
        "utc": "19:14:00"
      },
      ...
    ]
  }
]