C++ 如何查看::concat 2个不同的范围视图?
我正在尝试查看::concat 2个视图。我不明白我什么时候能做,什么时候不能做,为什么。任何帮助都会很好。这个问题听起来很相似,但并没有解决我的问题 我尝试了以下代码C++ 如何查看::concat 2个不同的范围视图?,c++,c++11,range-v3,C++,C++11,Range V3,我正在尝试查看::concat 2个视图。我不明白我什么时候能做,什么时候不能做,为什么。任何帮助都会很好。这个问题听起来很相似,但并没有解决我的问题 我尝试了以下代码 #include <iostream> #include <range/v3/all.hpp> using namespace ranges; int main () { // 'string' of spaces auto spaces = view::repeat_n(' ',4);
#include <iostream>
#include <range/v3/all.hpp>
using namespace ranges;
int main () {
// 'string' of spaces
auto spaces = view::repeat_n(' ',4); // 1
// prints [ , , , ]
std::cout << spaces << std::endl;
// 'string' of letters
auto letters = view::iota('a', 'a' + 4); // 2
// prints [a,b,c,d]
std::cout << letters << std::endl;
// 'string' from concat of letters and spaces
auto text = view::concat(letters,spaces); // 3
// prints [a,b,c,d, , , , ]
std::cout << text << std::endl;
// 'vector<string>' repeat letters
auto letter_lines = view::repeat_n(letters,3); // 4a
// prints [[a,b,c,d],[a,b,c,d],[a,b,c,d]]
std::cout << letter_lines << std::endl;
// 'vector<string>' repeat spaces
auto space_lines = view::repeat_n(spaces,3); // 4b
// prints [[ , , , ],[ , , , ],[ , , ,]]
std::cout << space_lines << std::endl;
// 'vector<string>' concat 2 repeated letter_lines
auto multi_letter_lines = view::concat(letter_lines,letter_lines); // 5
// prints [[a,b,c,d],[a,b,c,d],[a,b,c,d],[a,b,c,d],[a,b,c,d],[a,b,c,d]]
std::cout << multi_letter_lines << std::endl;
// 'vector<string>' from concat of letter_lines, and spaces_lines
// this doesn't work (well it compiles)
auto text_lines = view::concat(letter_lines,space_lines);
// this doesn't compile
std::cout << text_lines << std::endl; // 6 ERROR
// I expected [[a,b,c,d],[a,b,c,d],[a,b,c,d],[ , , , ],[ , , , ],[ , , , ]]
// This works
auto flat_text_lines = view::concat(letter_lines | view::join,
space_lines | view::join); // 7
// prints [a,b,c,d,a,b,c,d,a,b,c,d, , , , , , , , , , , , ]
std::cout << flat_text_lines << std::endl;
// but the structure is lost; it's a 'string', not a 'vector<string>'
}
#包括
#包括
使用名称空间范围;
int main(){
//空格的“字符串”
auto spaces=view::repeat_n(“”,4);//1
//印刷品[,]
标准::cout
note: template argument deduction/substitution failed:
concat.cpp:21:19: note: cannot convert ‘text_lines’ (type‘ranges::v3::concat_view<ranges::v3::repeat_n_view<ranges::v3::iota_view<char, int>>, ranges::v3::repeat_n_view<ranges::v3::repeat_n_view<char> > >’) to type ‘const ranges::v3::repeat_n_view<char>&’
std::cout << text_lines << std::endl;