C++ C++；确定税收的程序

因此，代码应该要求用户输入他们的收入，无论他们是联合申报还是单独申报，输出总收入和所得税，然后询问用户是否希望再次申报或退出。但由于某些原因，它会迫使您在继续之前输入每个输入两次。我知道我可能在代码中遗漏了一些简单的问题，但我无法解决它。使用Visual Studio，请帮助

int main()
{
    double income = 0;
    double taxRate = 0;
    double add = 0;
    double subtract = 0;
    double incomeTax = 0;
    string taxStatus = "";
    string file = "";
    string answer = "";
    top:
    cout << "\nPlease enter your income to calculate your taxes\n " << endl;
    cin >> income;
    while (!(cin >> income)) //get input
    {
        if (isdigit(income))
        {
            break;
        }

        else
        {
            //if input fails, run this
            cin.clear();
            cin.sync();
            cout << "\nSorry, that was not a valid number. Please enter a valid number\n ";
        }
    }
    cin.ignore(80, '\n');

    cout << "\nIf you will be filing singly, enter 's'. If you will be filing jointly, enter 'm'\n ";
    cin >> file;
    while (!(cin >> file)) //get input
    {
        if (file == "s" || "m")
        {
            cin.ignore(80, '\n');
            break;
        }

        else
        {
            //if input fails, run this
            cin.clear();
            cin.sync();
            cout << "\nThat is not a correct input, please enter s/m\n ";
        }
    }

        if (file == "s")
        {
            if (income <= 863)
            {
                taxRate = .022;
                subtract = 0;
                add = 0;
            }

            if (income >= 864 & income <= 2588)
            {
                taxRate = .033;
                subtract = 863;
                add = 25;
            }

            if (income >= 2589 & income <= 4313)
            {
                taxRate = .062;
                subtract = 2588;
                add = 85;
            }

            if (income > 4313)
            {
                taxRate = .075;
                subtract = 4313;
                add = 181;
            }
        }

        if (file == "m")
        {
            if (income <= 1726)
            {
                taxRate = .022;
                subtract = 0;
                add = 0;
            }

            if (income >= 1727 & income <= 5176)
            {
                taxRate = .033;
                subtract = 1726;
                add = 40;
            }

            if (income >= 5177 & income <= 8626)
            {
                taxRate = .062;
                subtract = 5176;
                add = 175;
            }

            if (income > 8626)
            {
                taxRate = .075;
                subtract = 8626;
                add = 390;
            }
        }

    incomeTax = ((income - subtract) * taxRate) + add;

    cout << "\nYour taxable income is " << income << endl;

    if (file == "s")
    {
        taxStatus = "Singly";
    }
    if (file == "m")
    {
        taxStatus = "Jointly";
    }
    cout << "\nand you are filing " << taxStatus << endl;

    cout << "\nThat means your income tax will be " << incomeTax << endl;

    cout << "\nWould you like to conduct another operation, y/n?\n ";
    cin >> answer;
    while (!(cin >> answer)) //get input
    {
        if (answer == "y")
        {
            goto top;
        }
        if (answer == "n")
        {
            break;
        }
        else
        {
            //if input fails, run this
            cin.clear();
            cin.sync();
            cout << "\nThat is not a correct input, please enter y/n. ";
        }
    }
    cin.ignore(80, '\n');

    system("PAUSE");

    return 0;
}

intmain（）
{
双收入=0；
双重税率=0；
双加=0；
双减法=0；
双incomeTax=0；
字符串taxStatus=“”；
字符串文件=”；
字符串答案=”；
顶部：
不能收入；
而（！（cin>>收入））//获取输入
{
if（isdigit（收入））
{
打破
}
其他的
{
//如果输入失败，请运行此命令
cin.clear（）；
cin.sync（）；
cout文件；
while（！（cin>>文件））//获取输入
{
如果（文件==“s”| |“m”）
{
cin.忽略（80，“\n”）；
打破
}
其他的
{
//如果输入失败，请运行此命令
cin.clear（）；
cin.sync（）；
你的代码中可能有一些小错误，比如：
if（file==“s”| |“m”
这是不正确的，应该是
if（file==“s”| | file==“m”）
而你有一个
&
这是一个引用，它采用变量地址或按位。你想要的是两个
&
，这意味着和

在这里，请执行以下操作：

while (!(isdigit(income))) // does after cin >> income;
{
        //if input fails, run this
        cin.clear();
        cin.sync();
        cout << "\nSorry, that was not a valid number. Please enter a valid number\n ";
        cin >> income
}

while (!(file == "s" || file == "m")) //this goes after cin >> file;
{
        cin.clear();
        cin.sync();
        cout << "\nThat is not a correct input, please enter s/m\n ";
        cin >> file;
}

while（！（isdigit（income））//在cin之后做>>收入；
{
//如果输入失败，请运行此命令
cin.clear（）；
cin.sync（）；
收入
}
而（！（file==“s”| | file==“m”）//这在cin>>文件之后；
{
cin.clear（）；
cin.sync（）；
cout>文件；
}
因此，我让它停止两次请求输入，因此感谢您的帮助。我仍然无法以美元格式输出所得税和所得税，并且在最后选择“y”时返回到程序的开头。有什么建议吗

int main()
{
    double income = 0; //double stores income input
    double taxRate = 0;//double stores tax rate
    double add = 0;//double stores value added
    double subtract = 0;//double stores value to be subtracted
    double incomeTax = 0;//double stores final income tax
    string taxStatus = "";//string stores status of single or joint
    string file = "";//string stores values of s or m
    string answer = "";//string stores values of y or n
    top:
    //asks user to input income value
    cout << "\nPlease enter your income to calculate your taxes\n " << endl;
    while (!(cin >> income)) //get input
    {
        if (isdigit(income) & income > 0)//if value is positive or numbers, exits loop
        {
            break;
        }

        else//if value is not valid, runs this
        {
            //if input fails, run this
            cin.clear();//clears line
            cin.sync();
            cout << "\nSorry, that was not a valid number. Please enter a valid number\n ";//asks user to input valid input
        }
    }
    cin.ignore(80, '\n');

    //asks user to enter whether filing singly or jointly
    cout << "\nIf you will be filing singly, enter 's'. If you will be filing jointly, enter 'm'\n ";
    while (!(cin >> file)) //get input
    {
        if (file == "s" || "m")//if input is valid, save and break loop
        {
            cin.ignore(80, '\n');
            break;
        }

        else//if value not valid, print message and repeat
        {
            //if input fails, run this
            cin.clear();
            cin.sync();
            cout << "\nThat is not a correct input, please enter s/m\n ";
        }
    }

        if (file == "s")//loop determines double values for single filing
        {
            if (income <= 863)//if income is under this value, use these settings
            {
                taxRate = .022;
                subtract = 0;
                add = 0;
            }

            if (income >= 864 & income <= 2588)//if income is between these values, use these settings
            {
                taxRate = .033;
                subtract = 863;
                add = 25;
            }

            if (income >= 2589 & income <= 4313)//if income is between these values, use these settings
            {
                taxRate = .062;
                subtract = 2588;
                add = 85;
            }

            if (income > 4313)//if income is above this value, use these settings
            {
                taxRate = .075;
                subtract = 4313;
                add = 181;
            }
        }

        if (file == "m")//sets double values if joint filing
        {
            if (income <= 1726)//if income is under this value, use these settings
            {
                taxRate = .022;
                subtract = 0;
                add = 0;
            }

            if (income >= 1727 & income <= 5176)//if income is between these values, use these settings
            {
                taxRate = .033;
                subtract = 1726;
                add = 40;
            }

            if (income >= 5177 & income <= 8626)//if income is between these values, use these settings
            {
                taxRate = .062;
                subtract = 5176;
                add = 175;
            }

            if (income > 8626)//if income is above this value, use these settings
            {
                taxRate = .075;
                subtract = 8626;
                add = 390;
            }
        }

    incomeTax = ((income - subtract) * taxRate) + add;//determines value of income tax

    cout << "\nYour taxable income is " << income << endl;//prints total income

    if (file == "s")//prints 'single' if 's' is selected
    {
        taxStatus = "Singly";
    }
    if (file == "m")//prints 'jointly' if 'm' selected
    {
        taxStatus = "Jointly";
    }
    cout << "\nand you are filing " << taxStatus << endl;//prints filing status

    cout << "\nThat means your income tax will be " << incomeTax << endl;//prints actual income tax

    cout << "\nWould you like to conduct another operation, y/n?\n ";//asks if user wants to do another filing
    while (!(cin >> answer)) //get input
    {
        if (answer == "y")//returns to start of program if yes
        {
            goto top;
        }
        if (answer == "n")//breaks loop if no
        {
            break;
        }
        else//if not valid answer, print message and run again
        {
            //if input fails, run this
            cin.clear();
            cin.sync();
            cout << "\nThat is not a correct input, please enter y/n. ";//asks user to try again
        }
    }
    cin.ignore(80, '\n');

    system("PAUSE");

    return 0;//ends program
}

intmain（）
{
double income=0；//double存储收入输入
双重税率=0；//双重存储税率
double add=0；//double存储增值
double subtract=0；//double存储要减去的值
double incomeTax=0；//double存储最终所得税
string taxStatus=“”；//字符串存储单个或关节的状态
string file=”“；//字符串存储s或m的值
string answer=“；//字符串存储y或n的值
顶部：
//要求用户输入收入值
cout income（）//获取输入
{
if（isdigit（income）&income>0）//如果值为正数或数字，则退出循环
{
打破
}
else//如果值无效，则运行此
{
//如果输入失败，请运行此命令
cin.clear（）；//清除行
cin.sync（）；
cout file））//获取输入
{
if（file==“s”| |“m”）//如果输入有效，保存并中断循环
{
cin.忽略（80，“\n”）；
打破
}
否则//如果值无效，则打印消息并重复
{
//如果输入失败，请运行此命令
cin.clear（）；
cin.sync（）；
cout
cin>>income；
和您的其他输入行都是重复的，因此您需要输入两次也就不足为奇了。
goto
有一个位置，但这种用法很容易避免。建议将其替换。替换为什么？我无论如何都无法使末尾的循环正常工作。如何以美元格式打印它们？如果使用，请使用其中一种（文件==“s”| |“m”或if（文件==“s”| |文件==“m”）不做任何更改，实际上不检查字符串中的字符。如果你回答了自己的问题，这很好，但是如果你有其他问题，你应该单独发布。如果你的问题在解决各种问题时不断变形为新的问题，这并不是一件好事，因为它会根据原始的q生成答案无效。