C++ 从地图中获取项目并添加到向量c++；

我在程序中死记硬背这段代码

JSONNode::const_iterator iter = root.begin();
    for (; iter!=root.end(); ++iter)
    {
        const JSONNode& arrayNode = *iter;
        std::string type = arrayNode["type"].as_string();
        if(type == "node")
        {
            std::string id = arrayNode["id"].as_string();
            double lat = arrayNode["lat"].as_float();
            double lon = arrayNode["lon"].as_float();
            Node node;
            node.SetId(id);
            node.SetLatitude(lat);
            node.SetLongitude(lon);
            nodesMap.insert( std::pair<std::string, Node>(id, node) );
        }
        else if(type == "way")
        {
            std::string wayId = arrayNode["id"].as_string();
            wayNode.SetId(wayId);
            std::vector<Node> collection;
            const JSONNode& wayNodes = arrayNode["nodes"];
            const JSONNode& nodes = wayNodes.as_array();
            JSONNode::const_iterator WayIter = nodes.begin();
            for (; WayIter!=nodes.end(); ++WayIter)
            {
                const JSONNode& arrayNode = *WayIter;
                std::string id = arrayNode.as_string();
                if(nodesMap.find(id) != nodesMap.end())
                {
                    collection.push_back(nodesMap.find(id)->second);
                    nodesMap.erase(id);  
                }
            }
            wayNode.SetNodesCollection(collection);
            std::cout<<"Item Id ->>>>>>>>>>>>>" << collection[2].GetId() << std::endl;
        }
    }

Node.cpp

Node::Node() {
}
Node::Node(const Node& orig) {
}
Node::~Node() {
}
Node::Node(std::string id, double lat, double lon){
    this->id = id;
    this->latitude = lat;
    this->longitude = lon;
}
void Node::SetLongitude(double longitude) {
    this->longitude = longitude;
}
double const & Node::GetLongitude() const {
    return longitude;
}
void Node::SetLatitude(double latitude) {
    this->latitude = latitude;
}
double const & Node::GetLatitude() const {
    return latitude;
}
void Node::SetId(std::string id) {
    this->id = id;
}
std::string const & Node::GetId() const {
    return id;
}

但当我尝试选择第二项的id时，std:：cout

---

按此方式修改副本构造函数。

为什么不使用隐式定义的副本构造函数，而不是定义新的副本构造函数？如果定义一个新的，为什么不使用初始化列表呢？@jogojapan我同意。这将是最简单的事情。通过删除代码来修复某些东西并不完全常见，接受它应该是值得庆祝的=）

Node::Node() {
}
Node::Node(const Node& orig) {
}
Node::~Node() {
}
Node::Node(std::string id, double lat, double lon){
    this->id = id;
    this->latitude = lat;
    this->longitude = lon;
}
void Node::SetLongitude(double longitude) {
    this->longitude = longitude;
}
double const & Node::GetLongitude() const {
    return longitude;
}
void Node::SetLatitude(double latitude) {
    this->latitude = latitude;
}
double const & Node::GetLatitude() const {
    return latitude;
}
void Node::SetId(std::string id) {
    this->id = id;
}
std::string const & Node::GetId() const {
    return id;
}

Node::Node(const Node& orig) {
    this->id = orig.id;
    this->latitude = orig.latitude;
    this->longitude = orig.longitude;
}