C++ 使用QPushButton而不是QComboBox更改QStackedLayout索引

我在Qt Creator中这样做。我只想用QPushButton而不是QComboBox来更改我的QStackedLayout。这可能吗？有人实施过这个吗？我从Qt文档中得到了很多示例，但所有示例都使用QComboBox（现在是我需要的QPushButton）。这是我的代码：

#mainwindow.cpp
#include "mainwindow.h"
#include "ui_mainwindow.h"

Dialog::Dialog()
{
    QVBoxLayout *mainlayout     =   new QVBoxLayout;
    QVBoxLayout *layouta        =   new QVBoxLayout;
    QVBoxLayout *layoutb        =   new QVBoxLayout;
    QPushButton *tombola        =   new QPushButton("A");
    QPushButton *tombolb        =   new QPushButton("B");
    QPushButton *tombolc        =   new QPushButton("C");
    QFrame      *framea         =   new QFrame;
    QFrame      *frameb         =   new QFrame;
    QStackedLayout *stackia     =   new QStackedLayout;

    layouta->addWidget(tombola);
    layoutb->addWidget(tombolb);

    framea->setLayout(layouta);
    frameb->setLayout(layoutb);
    framea->setMinimumSize(88,88);
    frameb->setMinimumSize(88,88);

    //building frame
    framea->setFrameShape(QFrame::StyledPanel);
    framea->setFrameShadow(QFrame::Raised);
    frameb->setFrameShape(QFrame::StyledPanel);
    frameb->setFrameShadow(QFrame::Raised);

    //get c button smaller
    tombolc->setMaximumWidth(33);

    stackia->addWidget(framea);
    stackia->addWidget(frameb);
    stackia->addWidget(tombolc);

    mainlayout->addLayout(stackia);
    QPushButton     *tombold    =   new QPushButton("D");
    mainlayout->addWidget(tombold);
    setLayout(mainlayout);

    connect(tombold, SIGNAL(clicked()), stackia, SLOT(setCurrentIndex(1))); //CONNECTOR
}

结果

Qt创建者说：

Object:：connect:没有这样的插槽QStackedLayout:：setCurrentIndex（1）

我犯了什么错

在搜索和询问4天后，我再次将connect（）和函数代码更改为：

连接器：

connect(tombold, SIGNAL(clicked()), stackia, SLOT(change_stack()));

功能： void Dialog:：change_stack（） { stackia->setCurrentIndex（1）； }

结果

但Qt创建者说：

对象：：连接：没有这样的插槽QStackedLayout：：更改\u堆栈（）

窗户立刻关上了

在我看来，我的代码有错误。但我不知道发生了什么错误，因此无法将布局内容/页面更改为其他页面。我犯了什么错？我相信这其实很简单，但我不知道错误在哪里

---

有什么建议吗？

您应该将

change\u stack

函数添加到您的

对话框

类中，并像这样连接到它：

class Dialog : public QWidget
{
    ...
    private slots:
    void change_stack();

private:
    QStackedLayout *stackia;
}

Dialog::Dialog
{
    ...
    connect(tombold, SIGNAL(clicked()), this, SLOT(change_stack()));
    ...
}


void Dialog::change_stack()
{
    stackia->setCurrentIndex(1);
}

Dialog::Dialog
{
    ...
    // This must be a member variable
    _stackia = new QStackedLayout();

    tombola->setProperty( "tabpage", 1 );
    tombolb->setProperty( "tabpage", 2 );
    tombolc->setProperty( "tabpage", 3 );

    connect( tombola, SIGNAL( clicked       () ),
             this   , SLOT  ( tombol_clicked() ) );
    connect( tombolb, SIGNAL( clicked       () ),
             this   , SLOT  ( tombol_clicked() ) );
    connect( tombolc, SIGNAL( clicked       () ),
             this   , SLOT  ( tombol_clicked() ) );
}

// This must be defined as slot in the header
void Dialog::tombol_clicked()
{
    int index = sender()->property( "tabpage" ).toInt();
    _stackia->setCurrentIndex( index );
}

关于

connect(tombold, SIGNAL(clicked()), stackia, SLOT(setCurrentIndex(1))); 

插槽只能具有与信号相同或更少的参数。 你能行

connect( sender  , SIGNAL( somethingHappened( const QString& ) ),
         receiver, SLOT  ( doSomething      ( const QString& ) ) );

// connect signal and ignore the parameter
connect( sender  , SIGNAL( somethingHappened( const QString& ) ),
         receiver, SLOT  ( doSomethingElse  (                ) ) );

你能做到吗

connect( sender  , SIGNAL( somethingHappened( const QString& ) ),
         receiver, SLOT  ( doSomething      ( const QString& ) ) );

// connect signal and ignore the parameter
connect( sender  , SIGNAL( somethingHappened( const QString& ) ),
         receiver, SLOT  ( doSomethingElse  (                ) ) );

但你不能这样做

// this will not work
connect( sender  , SIGNAL( somethingElseHappened(                ) ),
         receiver, SLOT  ( doSomething          ( const QString& ) ) );

您可能想要的是这样的：

class Dialog : public QWidget
{
    ...
    private slots:
    void change_stack();

private:
    QStackedLayout *stackia;
}

Dialog::Dialog
{
    ...
    connect(tombold, SIGNAL(clicked()), this, SLOT(change_stack()));
    ...
}


void Dialog::change_stack()
{
    stackia->setCurrentIndex(1);
}

Dialog::Dialog
{
    ...
    // This must be a member variable
    _stackia = new QStackedLayout();

    tombola->setProperty( "tabpage", 1 );
    tombolb->setProperty( "tabpage", 2 );
    tombolc->setProperty( "tabpage", 3 );

    connect( tombola, SIGNAL( clicked       () ),
             this   , SLOT  ( tombol_clicked() ) );
    connect( tombolb, SIGNAL( clicked       () ),
             this   , SLOT  ( tombol_clicked() ) );
    connect( tombolc, SIGNAL( clicked       () ),
             this   , SLOT  ( tombol_clicked() ) );
}

// This must be defined as slot in the header
void Dialog::tombol_clicked()
{
    int index = sender()->property( "tabpage" ).toInt();
    _stackia->setCurrentIndex( index );
}

---

非常感谢。但是我的mainwindow.cpp仍然是一样的。我已经在我的主窗口上实现了您的建议。h因此我将其更改为：。但实际上Qt创建者说：错误：Dialog:：change_stack（）的多个定义
首先在函数中定义
Dialog:：change_stack（）：
错误：Dialog:：change_stack（）的多个定义
我在代码上的错误是什么？