在C++中初始化类变量地址为null？

假设我有一个类，如下所示：

  class CBase
  {
      public:
         CBase(void){};
         ~CBase(void){};
         Sigintgen m_oSignals;// This is another class variable which i have not defined here.
   };

       main()
       {
           CBasec *ptr = new CBasec();
           I would want the following to happen as shown below:
           &(ptr->m_oSignals) should be equal to NULL. Can anyone please suggest me how to get this?
            &(ptr->m_oSignals) = NULL; //This was tried but compilation errors.    
       }

代码开始如下所示：

  class CBase
  {
      public:
         CBase(void){};
         ~CBase(void){};
         Sigintgen m_oSignals;// This is another class variable which i have not defined here.
   };

       main()
       {
           CBasec *ptr = new CBasec();
           I would want the following to happen as shown below:
           &(ptr->m_oSignals) should be equal to NULL. Can anyone please suggest me how to get this?
            &(ptr->m_oSignals) = NULL; //This was tried but compilation errors.    
       }

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高级感谢您的支持。

您不能。对象在声明后始终存在

相反，您可以在需要时动态分配Sigintgen，并让CBase存储一个指针，该指针可以以nullptr开头

---

或者使用std:：optional。

一般来说，如果使用std:：shared\u ptr而不是*，会更好，它将帮助您解决内存管理问题，并可能减少使用指针的恐惧，我假设您这样做是因为您没有将其用于Sigintgen m\u oSignals。成员变量的地址不能为空。让成员变量的地址等于NULL，您想实现什么？@PeterG。我之所以需要它来使用google测试框架进行单元测试