C++ 如何检测奇数值并打印错误消息

我试图成对地从文本文件中读取值，并对它们进行乘法和加法运算

这是文本文件的外观：

这是我的代码：

while (inFile >> positiveIntegerOne >> positiveIntegerTwo)
{
    if (positiveIntegerOne < 1) {
        if (positiveIntegerTwo < 1) {
            validIntegers = false;
            cout << "Integer one = " << positiveIntegerOne << "   Integer two = " << positiveIntegerTwo << "   Integer two is less than 1. \n";
        }
        validIntegers = false;
        cout << "Integer one = " << positiveIntegerOne << "   Integer two = " << positiveIntegerTwo << "   Integer one is less than 1. \n";
    }
    else {
        integersMultiplied = positiveIntegerOne * positiveIntegerTwo;
        integersAdded = positiveIntegerOne + positiveIntegerTwo;
        cout << "Integer one = " << positiveIntegerOne << "   Integer two = " << positiveIntegerTwo << "   Multipled = " << integersMultiplied << "   Added = " << integersAdded << "\n";
    }

}

while（infle>>positiveIntegerOne>>positiveIntegerTwo）
{
if（正整数<1）{
如果（正整数二小于1）{
validIntegers=false；
我想你可以做到以下几点

while (inFile >> positiveIntegerOne)
{
    if (inFile >> positiveIntegerTwo) {
        // You have a pair of numbers!
        if (positiveIntegerOne < 1) {
            if (positiveIntegerTwo < 1) {
                validIntegers = false;
                cout << "Integer one = " << positiveIntegerOne << "   Integer two = " << positiveIntegerTwo << "   Integer two is less than 1. \n";
            }
            validIntegers = false;
            cout << "Integer one = " << positiveIntegerOne << "   Integer two = " << positiveIntegerTwo << "   Integer one is less than 1. \n";
        }
        else {
            integersMultiplied = positiveIntegerOne * positiveIntegerTwo;
            integersAdded = positiveIntegerOne + positiveIntegerTwo;
            cout << "Integer one = " << positiveIntegerOne << "   Integer two = " << positiveIntegerTwo << "   Multipled = " << integersMultiplied << "   Added = " << integersAdded << "\n";
        }

    }
    else {
        // Print error for odd # of values!
    }
}

while（infle>>positiveIntegerOne）
{
如果（填充>>正整数二）{
//你有一对数字！
if（正整数<1）{
如果（正整数二小于1）{
validIntegers=false；
cout@drescherjm我想我知道你误解了什么，我不是说我的文件中不能有任何奇数，我的意思是如果“数字的数量是奇数”，然后显示错误message@drescherjm如果我的文件中有7个数字，那么我需要对前6个数字（3对）进行计算，然后计算最后一个数字（第七号）不属于一对，我需要打印出错误消息。如果文件中有6个数字，那么我只需对它们进行计算，并结束错误program@drescherjm这就是为什么我认为%，在这种情况下是没有意义的一件事，它没有处理的是行。如果你想验证每一行，它必须正好包含2个数字，代码将d有点不同。在这种情况下，你可以使用
std:：getline（）
到一个字符串中，然后
istringstream
从字符串中提取2个数字。谢谢！我不必担心行。对于我目前测试的内容，你的代码工作正常！我现在必须注销，但我会对你的代码进行一些研究。谢谢！
while (inFile >> positiveIntegerOne)
{
    if (inFile >> positiveIntegerTwo) {
        // You have a pair of numbers!
        if (positiveIntegerOne < 1) {
            if (positiveIntegerTwo < 1) {
                validIntegers = false;
                cout << "Integer one = " << positiveIntegerOne << "   Integer two = " << positiveIntegerTwo << "   Integer two is less than 1. \n";
            }
            validIntegers = false;
            cout << "Integer one = " << positiveIntegerOne << "   Integer two = " << positiveIntegerTwo << "   Integer one is less than 1. \n";
        }
        else {
            integersMultiplied = positiveIntegerOne * positiveIntegerTwo;
            integersAdded = positiveIntegerOne + positiveIntegerTwo;
            cout << "Integer one = " << positiveIntegerOne << "   Integer two = " << positiveIntegerTwo << "   Multipled = " << integersMultiplied << "   Added = " << integersAdded << "\n";
        }

    }
    else {
        // Print error for odd # of values!
    }
}