C# 自动编号字段
我想在帐户实体上创建自动编号插件。如果账户名称=摩根斯坦利,则账户编号=MORG0001;如果账户名称=摩根汽车,则账户编号=MORG0002;如果账户名称为ABC Tech,则账户编号应为ABCT00001 AccountNumber接受帐户名的前4个字符,并附加4个零,如果已经存在具有相同4个字符的帐户名,则将其递增1 方法名称:newAccunName() 我写的代码:C# 自动编号字段,c#,plugins,dynamics-crm,dynamics-crm-online,C#,Plugins,Dynamics Crm,Dynamics Crm Online,我想在帐户实体上创建自动编号插件。如果账户名称=摩根斯坦利,则账户编号=MORG0001;如果账户名称=摩根汽车,则账户编号=MORG0002;如果账户名称为ABC Tech,则账户编号应为ABCT00001 AccountNumber接受帐户名的前4个字符,并附加4个零,如果已经存在具有相同4个字符的帐户名,则将其递增1 方法名称:newAccunName() 我写的代码: public void updaterecord(EntityCollection account) {
public void updaterecord(EntityCollection account)
{
int totalrecords = account.Entities.Count;
string[] name = new string[totalrecords];
string append = "0000";
string value = "1";
int number = int.Parse(value);
string[] accountnumber = new string[totalrecords];
for (int i = 0; i < totalrecords; i++)
{
////check the accountname and take first 4 characters from it.
name[i] = account.Entities[i].Attributes["name"].ToString();
string partialstring = name[i].Substring(0, 4);
if (entity.Attributes.Contains("accountnumber") == false)
{
string anumber = string.Concat(partialstring, append, value);
entity.Attributes.Add("accountnumber", anumber.ToString());
}
else if (entity.Attributes.Contains("accountnumber") == true)
{
newaccountname(account);
}
}
}
public void newaccountname(EntityCollection account)
{
int totalrecords = account.Entities.Count;
string[] name = new string[totalrecords];
string[] accountnumber = new string[totalrecords];
for (int i = 0; i < totalrecords; i++)
{
string accountNumber = entity.GetAttributeValue<string>("accountnumber");
accountnumber[i] = account.Entities[i].Attributes["accountnumber"].ToString();
name[i] = account.Entities[i].Attributes["name"].ToString();
string paccountnumber = accountnumber[i].Substring(0, 4);
if(name[i] == paccountnumber)
{
//
}
}
}
}
public void updaterecord(EntityCollection帐户)
{
int totalrecords=account.Entities.Count;
字符串[]名称=新字符串[totalrecords];
字符串append=“0000”;
字符串值=“1”;
int number=int.Parse(值);
string[]accountnumber=新字符串[totalrecords];
对于(int i=0;i
好吧,我不打算为你解答测验:),但这里有一些提示
- 您需要先删除名称中的所有空格
- 您需要比较名称中的4个字符(在 删除空格)中仅包含名称的每4个字符 所以当你将“MORG0001”与“摩根汽车”进行比较时,你是 将“MORG”与“MORG”进行比较,在本例中,这两个词都是正确的
- 数一数你有多少“MORG”和新帐户将是多少 [前4个字母][0000][计数+1]
ArgumentOutOFRangeException
结果…请也查看本文: