C# 当源属性未映射时强制引发异常
在AutoMapper 2.2.1中,是否有任何方法可以配置映射,以便在未显式忽略属性时引发异常?例如,我有以下类和配置:C# 当源属性未映射时强制引发异常,c#,automapper,C#,Automapper,在AutoMapper 2.2.1中,是否有任何方法可以配置映射,以便在未显式忽略属性时引发异常?例如,我有以下类和配置: public class Source { public int X { get; set; } public int Y { get; set; } public int Z { get; set; } } public class Destination { public int X { get; set; } public i
public class Source
{
public int X { get; set; }
public int Y { get; set; }
public int Z { get; set; }
}
public class Destination
{
public int X { get; set; }
public int Y { get; set; }
}
// Config
Mapper.CreateMap<Source, Destination>();
Mapper.AssertConfigurationIsValid();
然后我将不会收到任何映射异常。我希望发生的是抛出AutoMapperConfigurationException
,因为没有显式忽略Source.Z
我希望我必须显式忽略Z属性,以便assertconfigurationsvalid
无异常运行:
Mapper.CreateMap<Source, Destination>()
.ForSourceMember(m => m.Z, e => e.Ignore());
Mapper.CreateMap()
.ForSourceMember(m=>m.Z,e=>e.Ignore());
目前,AutoMapper不会引发异常。如果我没有明确指定
Ignore
,我希望它抛出一个异常。如何执行此操作?以下是一个方法,该方法断言所有源类型属性都已映射:
public static void AssertAllSourcePropertiesMapped()
{
foreach (var map in Mapper.GetAllTypeMaps())
{
// Here is hack, because source member mappings are not exposed
Type t = typeof(TypeMap);
var configs = t.GetField("_sourceMemberConfigs", BindingFlags.Instance | BindingFlags.NonPublic);
var mappedSourceProperties = ((IEnumerable<SourceMemberConfig>)configs.GetValue(map)).Select(m => m.SourceMember);
var mappedProperties = map.GetPropertyMaps().Select(m => m.SourceMember)
.Concat(mappedSourceProperties);
var properties = map.SourceType.GetProperties(BindingFlags.Instance | BindingFlags.Public);
foreach (var propertyInfo in properties)
{
if (!mappedProperties.Contains(propertyInfo))
throw new Exception(String.Format("Property '{0}' of type '{1}' is not mapped",
propertyInfo, map.SourceType));
}
}
}
public静态void AssertAllSourcePropertiesMapped()
{
foreach(Mapper.GetAllTypeMaps()中的变量映射)
{
//这里是hack,因为源成员映射没有公开
类型t=类型(类型映射);
var configs=t.GetField(“_sourceMemberConfigs”,BindingFlags.Instance | BindingFlags.NonPublic);
var mappedSourceProperties=((IEnumerable)configs.GetValue(map)).Select(m=>m.SourceMember);
var mappedProperties=map.GetPropertyMaps().Select(m=>m.SourceMember)
.Concat(mappedSourceProperties);
var properties=map.SourceType.GetProperties(BindingFlags.Instance | BindingFlags.Public);
foreach(属性中的var propertyInfo)
{
如果(!mappedProperties.Contains(propertyInfo))
抛出新异常(String.Format(“未映射类型为“{1}”的属性“{0}”),
propertyInfo,map.SourceType));
}
}
}
它检查所有配置的映射,并验证每个源类型属性是否定义了映射(映射或忽略)
用法:
Mapper.CreateMap<Source, Destination>();
// ...
AssertAllSourcePropertiesMapped();
Mapper.CreateMap();
// ...
AssertAllSourcePropertiesMapped();
这是个例外
未映射类型为“YourNamespace.Source”的属性“Int32 Z”
如果忽略该属性,则一切正常:
Mapper.CreateMap<Source, Destination>()
.ForSourceMember(s => s.Z, opt => opt.Ignore());
AssertAllSourcePropertiesMapped();
Mapper.CreateMap()
.ForSourceMember(s=>s.Z,opt=>opt.Ignore());
AssertAllSourcePropertiesMapped();
TypeMap@MikeBantegui完全同意您的观点,但是源成员映射没有在TypeMap上公开,这让人感到遗憾。在答案的第一次编辑中,我只是使用了GetPropertyMaps()
,但令我惊讶的是,这里既没有源映射,也没有源映射作为TypeMap的公共属性公开