C# 如何使用一个actionlink在mvc4中下载多个文件?
行动: BinaryContentResult方法:C# 如何使用一个actionlink在mvc4中下载多个文件?,c#,asp.net-mvc,asp.net-mvc-4,C#,Asp.net Mvc,Asp.net Mvc 4,行动: BinaryContentResult方法: public ActionResult Download(string filename) { var filenames = filename.Split(',').Distinct(); var dirSeparator = Path.DirectorySeparatorChar; foreach (var f in filenames) {
public ActionResult Download(string filename)
{
var filenames = filename.Split(',').Distinct();
var dirSeparator = Path.DirectorySeparatorChar;
foreach (var f in filenames)
{
if (String.IsNullOrWhiteSpace(f)) continue;
var path = AppDomain.CurrentDomain.BaseDirectory + "Uploads" + dirSeparator + f;
if (!System.IO.File.Exists(path)) continue;
return new BinaryContentResult
{
FileName = f,
ContentType = "application/octet-stream",
Content = System.IO.File.ReadAllBytes(path)
};
}
return View("Index");
}
视图:
但是actionlink只需下载一个(First)文件。一种可能性是将所有文件压缩到一个文件中,然后将此压缩文件返回给客户端。此外,您的代码还有一个巨大的缺陷:在将整个文件内容返回到客户端之前,您正在将其加载到内存中:
System.IO.file.ReadAllBytes(path)
,而不是仅使用专门为此目的设计的FileStreamResult
。您似乎用BinaryContentResult
类重新发明了一些轮子
因此:
公共操作结果下载(字符串文件名)
{
var filenames=filename.Split(',').Distinct();
字符串zipFile=Zip(文件名);
返回文件(zip,“应用程序/八位字节流”,“download.zip”);
}
私有字符串Zip(IEnumerable文件名)
{
//在这里,您可以使用任何可用的zip库,例如SharpZipLib
//创建包含所有文件的zip文件并返回物理
//此zip文件在磁盘上的位置
}
为什么要发明一个较慢版本的FileStreamResult
?HTTP不支持这一点。如何使用FileStreamResult
?
public class BinaryContentResult : ActionResult
{
public string ContentType { get; set; }
public string FileName { get; set; }
public byte[] Content { get; set; }
public override void ExecuteResult(ControllerContext context)
{
context.HttpContext.Response.ClearContent();
context.HttpContext.Response.ContentType = ContentType;
context.HttpContext.Response.AddHeader("content-disposition", "attachment; filename=" + FileName);
context.HttpContext.Response.BinaryWrite(Content);
context.HttpContext.Response.End();
}
}
@{
foreach (var item in Model)
{
@Html.ActionLink("Link","Index", "FileUpload", new { postid = item.PostId })
}
}
public ActionResult Download(string filename)
{
var filenames = filename.Split(',').Distinct();
string zipFile = Zip(filenames);
return File(zip, "application/octet-stream", "download.zip");
}
private string Zip(IEnumerable<string> filenames)
{
// here you could use any available zip library, such as SharpZipLib
// to create a zip file containing all the files and return the physical
// location of this zip on the disk
}