C# 使用Roslyn发出Win32Icon

如何给我的roslyn编译器输出一个图标

在codedom中，我可以简单地使用编译器选项并将其添加为“/win32icon:”

但是在罗斯林怎么办

我已经知道了

   var syntaxTree = CSharpSyntaxTree.ParseText(File.ReadAllText("program.cs"));
         CSharpCommandLineArguments arguments = new CSharpCommandLineArguments();
        arguments.Win32Icon = @"ICON PATH";

        CSharpCompilation compilation = CSharpCompilation.Create(
            "program",
            new[] { syntaxTree },
            new[] { MetadataReference.CreateFromFile(typeof(object).Assembly.Location) },
            new CSharpCompilationOptions(OutputKind.ConsoleApplication));

        ResourceWriter rs = new ResourceWriter("res.resources");

        var resourceDescription = new ResourceDescription("program.Resources.resources", () => new MemoryStream(File.ReadAllBytes("res.resources")), true);

        using (var dllStream = new MemoryStream())
        using (var pdbStream = new MemoryStream())
        {
            var emitResult = compilation.Emit(dllStream, pdbStream, null,null, manifestResources: new [] {resourceDescription});
            if (emitResult.Success)
            {
                File.WriteAllBytes("test.exe",dllStream.GetBuffer());
                Console.WriteLine("compiled");
            }
            else
            {
                Console.WriteLine("foutje: {0}", emitResult.Diagnostics[0].ToString());
            }
        }

        Console.ReadLine();

---

已经谢谢你的帮助了

您需要传入win32Resources选项以发射，通过创建，该选项采用

Stream iconicoformat

参数

compilation.Emit(
    peStream: peStream,
    pdbStream: pdbStream,
    win32Resources: compilation.CreateDefaultWin32Resources(..., iconInIcoFormat: File.Open("<pathTo.ico>")))

compilation.Emit(
peStream:peStream，
PDB流：PDB流，
win32Resources:compilation.CreateDefaultWin32Resources（…，iconicoFormat:File.Open（“”））

更详细的exmaple是